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2 answers:
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Answer:
about 2.81 km/h
Step-by-step explanation:
It can be useful to draw a diagram.
The lines pointing to due north from points B and P are parallel, so the angle BCP and the bearing of point C from P are the same, 30°. The angle BPC will be the difference of bearings of B and C at P, so is 47-30=17°. This is enough information to solve the triangle using the Law of Sines:
PB/sin(C) = CB/sin(P)
CB = PB·sin(P)/sin(C) = (1200 m)·sin(17°)/sin(30°) ≈ 701.7 m
The speed of the boat is then ...
x = distance/time = (0.7017 km)/(1/4 h) = 2.8068 km/h
Alright here we go:
First, you would need to do a little cross multiplication/division.
(X is the segment we’re looking for)
You would put 1.5/2.25 and then 1.4/x. After that, multiply 2.25x1.4 to get 3.15. After that divide 3.15 by 1.5 to complete the cross multiplication, getting you 2.1.
So there is your answer, 2.1! I really hope that’s right!
Work wise it should look something like the picture attached, sorry if it’s messy.
First, you would need to do a little cross multiplication/division.
(X is the segment we’re looking for)
You would put 1.5/2.25 and then 1.4/x. After that, multiply 2.25x1.4 to get 3.15. After that divide 3.15 by 1.5 to complete the cross multiplication, getting you 2.1.
So there is your answer, 2.1! I really hope that’s right!
Work wise it should look something like the picture attached, sorry if it’s messy.