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AveGali [126]
4 years ago
10

300 pounds of oranges were purchased at $0.24 per pound. The desired markup is 50% based on selling price, but 21% spoilage is e

xpected. What should the selling price per pound be? (Round your answer to the nearest cent)
Mathematics
1 answer:
andrezito [222]4 years ago
8 0
1. The problem indicates that 300 pounds of oranges were purchased at $0.24 per pound, so the cost is:
 
 300x$0.24=$72
 
 2. A percent of 21% spoilage is expected, which means that 89% of 300 pounds of oranges left, is:
 
 300x0.89=267 pounds of oranges
 
 3. We want to calculate the selling price per pound of 267 pounds of oranges, so let's call this value "x":
 
 Markup %=(Markup/cost)x100
 
 Markup=267x-72
  
 4. The desired markup, based on selling price, is 50%. So, when we substitute the values, we obtain:
 
 (267x-72/72)x100=50
 
 5. Let's clear the "x":
 
 (26700x-7200/72)=50
 26700x-7200=50x72
 26700x-7200=3600
 26700x=3600+7200
 x=10800/26700
 x=$0.40
 x=40 cents
 
 What should the selling price per pound be?
 
 The answer is: 40 cents or $0.40
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statuscvo [17]

Answer: The answer is \textup{The other root is }\dfrac{8}{3}~\textup{and}q=40.Step-by-step explanation:  The given quadratic equation is[tex]3x^2+7x-q=0\\\\\Rightarrow x^2-\dfrac{7}{3}x-\dfrac{q}{3}=0.

Also given that -5 is one of the roots, we are to find the other root and the value of 'q'.

Let the other root of the equation be 'p'. So, we have

p-5=-\dfrac{7}{3}\\\\\\\Rightarrow p=5-\dfrac{7}{3}\\\\\\\Rightarrow p=\dfrac{8}{3},

and

p\times(-5)=-\dfrac{q}{3}\\\\\\\Rightarrow \dfrac{8}{3}\times 5=\dfrac{q}{3}\\\\\\\Rightarrow q=40.

Thus, the other root is \dfrac{8}{3} and the value of 'q' is 40.

3 0
3 years ago
Six oranges cost 5.34. How much does 1 Orange cost?
ikadub [295]

Divide the total cost with the amount there is

5.34/6 = 0.89

Each orange costs $0.89, or 89 cents

hope this helps

6 0
3 years ago
Read 2 more answers
4 2/3 + 1 3/4 give your answer as a mixed number
Anna71 [15]

Answer:

6 5/12

Step-by-step explanation:

Given the expression :

4 2/3 + 1 3/4

The sum of the numbers :

4 2/3 + 1 3/4

14/3 + 7/4

L.C.M of 3 and 4 = 12

(56 + 21) / 12

77 / 12

= 6 5/12

7 0
3 years ago
Three corporations each own land. Corporation A owns 3.2 × 105 acres, corporation B owns 4 × 104 acres, and corporation C owns 4
elena-14-01-66 [18.8K]
First of all, we know that
Corporation A owns 3.2 × 10^5 acres
Corporation B owns 4×10^4 acres
Corporation C owns 4.3×10^5 acres
To compare which corporation owns the most land, we need to have the same unit of exponent which is 10^4, so we need to change Corporation A and Corporation C:
Corporation A: 3.2×10^5
Corporation A: 32×10^4
Corporation C: 4.3×10^5
Corporation C: 43×10^4
In this case, compare all three corporation. We see that Corporation C owns the most land.
Lastly,
To find “ How many times greater is corporation A’s land than corporation B’s land ", take:
Corporation A / Corporation B
=32×10^4/4×10^4
=32/4×10^4/10^4
=8×10^4-4
=8×10^0
=8×1
=8 times is your final answer. Hope it help!
5 0
4 years ago
Read 2 more answers
Me podrían ayudar a contestar estas preguntas, por favorspeak spanish
lisabon 2012 [21]

En un parallelogramo, los lados opuestos son paralelos. De la misma forma, los angulos opuestos son iguales y los angulos adjacentes suman 180 grados.

Con ello, podemos decir que:

a. Los lados RS y UT son paralelos.

b. Los lados RU y ST son paralelos.

c. El angulo en U es igual al angulo en S pues son opuestos

d. Los angulos en S y T son adjacentes . Esto quiere decir que, su suma es igual a 180 grados.

e. El angulo en R es igual al angulo en T pues son opuestos.

f. De forma similar al caso d, los angulos U y R son adjacentes, su suma es 180 grados.

7 0
1 year ago
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