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AveGali [126]
3 years ago
10

300 pounds of oranges were purchased at $0.24 per pound. The desired markup is 50% based on selling price, but 21% spoilage is e

xpected. What should the selling price per pound be? (Round your answer to the nearest cent)
Mathematics
1 answer:
andrezito [222]3 years ago
8 0
1. The problem indicates that 300 pounds of oranges were purchased at $0.24 per pound, so the cost is:
 
 300x$0.24=$72
 
 2. A percent of 21% spoilage is expected, which means that 89% of 300 pounds of oranges left, is:
 
 300x0.89=267 pounds of oranges
 
 3. We want to calculate the selling price per pound of 267 pounds of oranges, so let's call this value "x":
 
 Markup %=(Markup/cost)x100
 
 Markup=267x-72
  
 4. The desired markup, based on selling price, is 50%. So, when we substitute the values, we obtain:
 
 (267x-72/72)x100=50
 
 5. Let's clear the "x":
 
 (26700x-7200/72)=50
 26700x-7200=50x72
 26700x-7200=3600
 26700x=3600+7200
 x=10800/26700
 x=$0.40
 x=40 cents
 
 What should the selling price per pound be?
 
 The answer is: 40 cents or $0.40
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Lets take   (-4) - (-6) 
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6 0
3 years ago
HELP PLEASE!!!!
kumpel [21]

Answer:

The rational numbers are \frac{11}{3}, 6.25, 0.01045,\sqrt{\frac{16}{81}},0.\bar{42} and the irrational functions are \sqrt{48},\sqrt{\frac{3}{16}}.

Step-by-step explanation:

A rational number can be expressed in the form of \frac{p}{q}, where p and q are integers and q is not equal to 0. For example 2,3.5,\frac{2}{5},....

An irrational function can not be expressed in the form of \frac{p}{q}, where p and q are integers and q is not equal to 0. For example \sqrt{2},\sqrt{3},\sqrt{5},....

If any number is multiplied by a irrational number then the resultant number is an irrational number.

By the above definition we can conclude that:

The number \frac{11}{3} is a rational number.

\sqrt{48}=\sqrt{16\times 3}=4\sqrt{3}

Therefore \sqrt{48} is an irrational number.

6.25=\frac{625}{100}=\frac{25}{4}

Therefore 6.25 is a rational number.

0.01045=\frac{1045}{100000}=\frac{209}{20000}

Therefore 0.01045 is a rational number.

\sqrt{\frac{16}{81}}=\frac{4}{9}

The number \frac{16}{81} is a rational number.

\sqrt{\frac{3}{16}}=\frac{\sqrt{3}}{4}

The number \frac{3}{14} is an irrational number.

0.\bar{42}=\frac{42}{99}

Therefore 0.\bar{42} is an irrational number. The numbers with recursive bar are always rational numbers.

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lbvjy [14]

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The answer is A,C, and D

Step-by-step explanation:

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