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2 years ago

Which best explains why a crystal is incompressible?.

Chemistry

1 answer:

Katen [24]2 years ago

6 0

Answer:

There is little if any, space left between its adjacent molecules.

Good luck!

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liquid disilicon hexachloride reacts with water to form solid silicon dioxide, hydrogen chloride gas, and hydrogen gas. be sure

kodGreya [7K]

The liquid disilicon hexachloride reacts with water to form solid silicon dioxide, hydrogen chloride gas and hydrogen gas are

$Si{2}Cl{6} (l) + 4H{2}O (l) ------ > 2SiO{2} (s) + 6HCl (g) + H{2} (g)$

When liquid disilicon hexachloride reacts with water to form solid silicon dioxide , hydrogen chloride gas and hydrogen gas , the following chemical equation is:

$Si{2}Cl{6} (l) + H{2}O (l) ------ > SiO{2} (s) + HCl (g) + H{2} (g)$

now , we have to balance the eqaution,

Reactants product

Si 2 1

Cl 6 1

H 2 3

O 1 2

Multiply 4 with $H{2}O$ 2 with $SiO{2}$ and 6 with HCL, we get

$Si{2}Cl{6} (l) + 4H{2}O (l) ------ > 2SiO{2} (s) + 6HCl (g) + H{2} (g)$

now ,

Reactant Product

Si 2 2

Cl 6 6

H 8 8

O 4 4

Thus, we get the desire equtions.

The liquid disilicon hexachloride reacts with water to form solid silicon dioxide, hydrogen chloride gas and hydrogen gas are

$Si{2}Cl{6} (l) + 4H{2}O (l) ------ > 2SiO{2} (s) + 6HCl (g) + H{2} (g)$

To learn more about Chemical equation here

brainly.com/question/28294176

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7 0

1 year ago

Iron iii chloride+ copper ii sulfate balanced equation

Bogdan [553]

Answer:

Iron (iii) chloride reacts with copper (ii) sulfate to give iron sulfate and copper chloride.

Explanation:

The balanced equation of iron iii chloride+ copper ii sulfate is as follows.

$$2FeCl_{3}+3CuSO_{4} \to Fe_{2}(SO_{4})_{3}+3CuCl_{2}$

5 0

4 years ago

which moving body has no acceleration? a.a satilite orbiting at a constant speed b.a person rnning once around a track at a cons

RoseWind [281]

The answer is D. for sure i took the test no acceleration means no turning going straight no turns i hope i helped

8 0

3 years ago

Read 2 more answers

Calculate ΔH and ΔStot when two copper blocks, each of mass 10.0 kg, one at 100°C and the other at 0°C, are placed in contact in

ira [324]

Explanation:

The given data is as follows.

m = 10.0 kg = 10,000 g (as 1 kg = 1000 g)

Initial temp. of block 1, $T_{1} = 100^{o}C$ = (100 + 273) K = 373 K

Initial temp. of block 2, $T_{2} = 0^{o}C$ = (0 + 273) K = 273 K

So, heat released by block 1 = heat gained by block 2

$mC \Delta T = mC \times \Delta T$

$10000 g \times 0.385 \times (T_{f} - 100)^{o}C = 10000 g \times 0.385 \times (0 - T_{f})^{o}C$

$T_{f} - 100^{o}C = 0^{o}C - T_{f}$

$2T_{f} = 100^{o}C$

$T_{f} = 50^{o}C$

Convert temperature into kelvin as (50 + 273) K = 323 K.

Also, we know that the relation between enthalpy and temperature change is as follows.

$\Delta H = mC \Delta T$

= $10000 g \times 0.385 J/K g \times 323 K$

= 1243550 J

or, = 1243.5 kJ

Now, calculate entropy change for block 1 as follows.

$\Delta S_{1} = mC ln \frac{T_{f}}{T_{i}}$

= $10000 g \times 0.385 J/K g \times ln \frac{323}{373}$

= $10000 g \times 0.385 J/K g \times -0.143$

= -554.12 J/K

Now, entropy change for block 2 is as follows.

$\Delta S_{2} = mC ln \frac{T_{f}}{T_{i}}$

= $10000 g \times 0.385 J/K g \times ln \frac{323}{273}$

= $10000 g \times 0.385 J/K g \times 0.168$

= 647.49 J/K

Hence, total entropy will be sum of entropy change of both the blocks.

$\Delta S_{total} = \Delta S_{1} + \Delta S_{2}$

= -554.12 J/K + 647.49 J/K

= 93.37 J/K

Thus, we can conclude that for the given reaction $\Delta H$ is 1243.5 kJ and $\Delta S_{total}$ is 93.37 J/K.

6 0

3 years ago

Red light has a longer _____ than violet light

irinina [24]

Answer:

wavelength

5 0

3 years ago

Read 2 more answers