If you negate reaction 2 and combine the reactions, which substances do not cancel?

How many moles of carbon dioxide gas can be produced when 7.94 moles of benzene (C6H6) react with excess oxygen? Be sure to show

Sliva [168]

The balanced equation is

2 C6H6 +15 O2 = 12 CO2 + 6 H2O 

the ratio between C6H6 and CO2 is 2 : 12 

moles CO2 produced = 7.94 x 12 / 2 =47.6

6 0

4 years ago

- Unit 1 Worksheet 4

3241004551 [841]

I think it is C or F

4 0

3 years ago

How many moles of iron (iii) oxide are in a 120 gram sample of fe2o3?

AnnyKZ [126]

First find the molar mass of Fe2O3, after you would want to do this
120 g Fe2O3 x 1 mol = # mol
Molar Mass

3 0

3 years ago

If 100 mg of ferrocene is reacted with 75 mg of anhydrous aluminum chloride and 40 microliters of acetyl chloride and 100 mg of

Alex_Xolod [135]

Answer:

81.3 %

Explanation:

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

For ferrocene:-

Mass of ferrocene = 100 mg = 0.1 g

Molar mass of ferrocene = 186.04 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{0.1\ g}{186.04\ g/mol}$

$Moles\ of\ ferrocene= 0.0005375\ mol$

For acetyl chloride:-

Volume = 40 microliters = 0.04 mL

Density = 1.1 g / mL

Density is defined as:-

$\rho=\frac{Mass}{Volume}$

or,

$Mass={\rho}\times Volume=1.1\times 0.04\ g=0.044 g$

Mass of acetyl chloride = 0.044 g

Molar mass of acetyl chloride = 78.49 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{0.044\ g}{78.49\ g/mol}$

$Moles\ of\ acetyl\ chloride= 0.0005606\ mol$

As per the reaction stoichiometry, one mole of ferrocene reacts with one mole of acetyl chloride to give one mole of monoacetylferrocene

Limiting reagent is the one which is present in small amount. Thus, ferrocene is limiting reagent.

The formation of the product is governed by the limiting reagent. So,

one mole of ferrocene on reaction forms one mole of monoacetylferrocene

0.0005375 mole of ferrocene on reaction forms 0.0005375 mole of monoacetylferrocene

Moles of product formed = 0.0005375 moles

Molar mass of monoacetylferrocene = 228.07 g/mole

Mass of monoacetylferrocene produced = Moles*molecular weight = 0.0005375*228.07 g = 0.123 grams = 123 mg

Given experimental yield = 100 mg

% yield = (Experimental yield / Theoretical yield) × 100 = (100/ 123) × 100 = 81.3 %

5 0

3 years ago

10. Summarize the effect of hydrogen bonding on boiling point.

oksano4ka [1.4K]

Answer:

10. it increases the boiling point because it is a stone bond and will require much energy to break it.

11.So, to boil liquid water, all hydrogen bonds have to be broken and it requires a large amount of energy. This isn't the case in HF; all hydrogen bonds need not to be broken, and therefore a lesser amount of energy is required. So HF boils at a much lower temperature as compared to water even though F has high electronegativity but the force of attraction or the intermolecular is is weak

7 0

2 years ago