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tatuchka [14]
3 years ago
11

If you negate reaction 2 and combine the reactions, which substances do not cancel?

Chemistry
1 answer:
olya-2409 [2.1K]3 years ago
4 0

"Mg, MgO, and O2 "

THOSE ARE THE ANSWERS!


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8 0
2 years ago
Is oxygen a beginning substance or ending substance?
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Answer:

Explanation:

The substances that are present at the beginning are called reactants and the substances present at the end are called products. Sometimes when reactants are put into a reaction vessel, a reaction will take place to produce products. Reactants are the starting materials, that is, whatever we have as our initial ingredients.Oxygen, a colorless, odorless, tasteless gas essential to living organisms, being taken up by animals, which convert it to carbon dioxide; plants, in turn, utilize carbon dioxide as a source of carbon and return the oxygen to the atmosphere. Oxygen forms compounds by reaction with practically any other element.

4 0
3 years ago
Read 2 more answers
The electron configuration of a neutral atom is 1s22s22p63s2. Write a complete set of quantum numbers for each of the electrons.
Pavlova-9 [17]

Answer:

The four quantum number for each electron will be:

1s^{2}

n=1;l=0;m=0;s=+\frac{1}{2}/-\frac{1}{2}

2s^{2}

n=2;l=0;m=0;s=+\frac{1}{2}/-\frac{1}{2}

2p^{6}

n=1;l=1;\\m=+1,0.-1 \\s=+\frac{1}{2}/-\frac{1}{2}

3s^{2}

n=3;l=0;m=0;s=+\frac{1}{2}/-\frac{1}{2}

Explanation:

As the element is neutral, the number of protons will be equal to number of electrons which will be the atomic number of the element.

Number of electrons =12

Atomic number = 12

Element : Magnesium

The principal shell is represented by "n"

i) For "s" subshell the value of l =0 (azimuthal quantum number) thus m (magnetic quantum number)= 0

The two electrons in s subshell will have either plus half or minus half spin quantum number

ii) for "p" subshell the value for l =1

thus m = 0 or +1 or -1

The two electrons in each orbital will have either plus half or minus half spin quantum number

8 0
2 years ago
Which equation shows how to calculate how many grams (g) of KOH would be needed to fully react with 4 mol Mg(OH)2? The balanced
bazaltina [42]
Mole ratio:

MgCl₂ + 2 KOH = Mg(OH)₂ + 2 KCl

2 moles KOH ---------------- 1 mole Mg(OH)₂
moles KOH ------------------- 4 moles Mg(OH₂)

moles KOH = 4 x 2 / 1

= 8 moles of  KOH

molar mass KOH = 56 g/mol

mass of KOH = n x mm

mass of  KOH = 8 x 56

= 448 g of KOH 

hope this helps!

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