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Leya [2.2K]
3 years ago
8

A runner traveled 3 mi in the same time that a cyclist traveled 5 mi. The speed of the cyclist was 2 mph greater than that of th

e runner. What was the​ cyclist's speed?
Mathematics
1 answer:
Contact [7]3 years ago
3 0

Answer:

5 mph.

Step-by-step explanation:

Let the runner travel at x miles an hour , then the cyclist travels at 5/ 3 * x

= 5/3 x  miles an hour.

So we have the equation

5/3 x - x = 2    ( since the cyclist was  travelling at 2  mph faster).,

2/3 x = 2

x = 3/2 * 2 = 3 mph.

So the cyclists speed was  3 * 5/3

= 5 mph.

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Step-by-step explanation:

<h3><u>G</u><u>i</u><u>v</u><u>e</u><u>n</u><u> </u><u>Inform</u><u>ation</u><u> </u><u>:</u></h3>

  • Ryan spent 1/3 of his monthly salary for rent and 1/7 of his monthly salary for his utility bill.
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<h3><u>T</u><u>o</u><u> </u><u>calculate</u><u> </u><u>:</u></h3>

  • His monthly salary.

<h3><u>C</u><u>a</u><u>l</u><u>c</u><u>u</u><u>l</u><u>a</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>:</u></h3>

Let us assume his monthly salary as x. According to the question,

➝ Money spent on rent + Money spent for utility bill + Remaining money = His salary

\longrightarrow\sf {\dfrac{1}{3}x + \dfrac{1}{7}x + 759 = x} \\

\longrightarrow\sf {\dfrac{7x + 3x + 15939}{21}= x} \\

\longrightarrow\sf {\dfrac{10x+ 15939}{21}= x} \\

\longrightarrow\sf {10x+ 15939= 21x} \\

\longrightarrow\sf {15939= 21x - 10x} \\

\longrightarrow\sf {15939= 11x} \\

\longrightarrow\sf {\cancel{\dfrac{15939}{11}}= x} \\

\longrightarrow\underline{\boxed{\bf {1449= x}}} \\

<u>Therefore,</u><u> </u><u>his</u><u> </u><u>monthly</u><u> </u><u>income</u><u> </u><u>is</u><u> </u><u>$</u><u>1</u><u>4</u><u>4</u><u>9</u><u>.</u>

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