The answer is 10. because median means middle so 10 is the middle #.
Answer:
b & c for sure
Step-by-step explanation:
............
This is always ''interesting'' If you see an absolute value, you always need to deal with when it is zero:
(x-4)=0 ===> x=4,
so that now you have to plot 2 functions!
For x<= 4: what's inside the absolute value (x-4) is negative, right?, then let's make it +, by multiplying by -1:
|x-4| = -(x-4)=4-x
Then:
for x<=4, y = -x+4-7 = -x-3
for x=>4, (x-4) is positive, so no changes:
y= x-4-7 = x-11,
Now plot both lines. Pick up some x that are 4 or less, for y = -x-3, and some points that are 4 or greater, for y=x-11
In fact, only two points are necessary to draw a line, right? So if you want to go full speed, choose:
x=4 and x= 3 for y=-x-3
And just x=5 for y=x-11
The reason is that the absolute value is continuous, so x=4 works for both:
x=4===> y=-4-3 = -7
x==4 ====> y = 4-11=-7!
abs() usually have a cusp int he point where it is =0
Hope it helps, despite being this long!
A <em>circle</em> is a figure <u>bounded</u> by a <em>curved</em> side which is referred to as <em>circumference</em>. Thus the area of the <u>shaded</u> region is option D. 81.65.
A <em>circle</em> is a figure<u> bounded</u> by a <em>curved</em> side which is referred to as <u>circumference</u>. Some of its <u>parts</u> are radius, diameter, sector, arc, etc.
The area of a <u>circle</u> can be determined by the given <em>expression:</em>
Area = π
where r is the <u>radius</u> of the circle and π = 
So, the area of the <u>shaded</u> region can be determined as:
Area of the <em>shaded</em> region = <em>area </em>of the <u>larger</u> circle - <em>area</em> of the <u>smaller</u> circle
Area of the<em> shaded </em>region = π
- π
= π (46.24 - 20.25)
=
x 25.99
= 
<u>Area</u> of the <em>shaded</em> region = 81.683
Thus the<u> appropriate</u> answer to the question is option D. 81.65.
For more clarifications on the area of a circle, visit: brainly.com/question/3747803
#SPJ1
Answer:
im guessing -1
Step-by-step explain
well it would be greater than -1x-1