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mart [117]
2 years ago
7

5(20 + _ )= 100 + 85 I need help fast

Mathematics
2 answers:
Zanzabum2 years ago
5 0

Answer:

  • 17

Step-by-step explanation:

  • 5(20 + x) = 100 + 85
  • 100 + 5x = 100 + 85
  • 5x = 85
  • x = 17
kompoz [17]2 years ago
3 0

Answer:

_ = 5

Step-by-step explanation:

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A certain process for removing copper from copper bearing ore had been in use for a period of time, and it is known that this pr
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Answer:

d. Ore treated with the new process.

Step-by-step explanation:

This is a common practice in statistics, in which we use a sample of a population to infer something about the entire population. We should use a sample of 100.

For example, if we want to know the proportion of residents of Buffalo, New York, who are Bills fans, we are going to take a sample of like, 100 residents, and then use this to estimate for the entire city.

In this problem, we have that:

A new process that is supposed to increase the recovered amount is being tested. In a simple random sample of 100 batches of ore, an average of 42 pounds per ton were recovered using the new process.

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d. Ore treated with the new process.

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2 years ago
A quality control specialist at a pencil manufacturer pulls a random sample of 45 pencils from the assembly line. The pencils ha
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Answer:

The P-value you would use to test the claim that the population mean of  pencils produced in that factory have a mean length equal to 18.0 cm is 0.00736.

Step-by-step explanation:

We are given that a quality control specialist at a pencil manufacturer pulls a random sample of 45 pencils from the assembly line.

The pencils have a mean length of  17.9 cm. Given that the population standard deviation is 0.25 cm.

Let \mu = <u><em>population mean length of  pencils produced in that factory.</em></u>

So, Null Hypothesis, H_0 : \mu = 18.0 cm     {means that the population mean of  pencils produced in that factory have a mean length equal to 18.0 cm}

Alternate Hypothesis, H_A : \mu\neq 18.0 cm     {means that the population mean of  pencils produced in that factory have a mean length different from 18.0 cm}

The test statistics that will be used here is <u>One-sample z-test</u> statistics because we know about the population standard deviation;

                           T.S.  =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean length of pencils = 17.9 cm

           \sigma = population standard deviation = 0.25 cm

           n = sample of pencils = 45

So, <u><em>the test statistics</em></u> =  \frac{17.9-18.0}{\frac{0.25}{\sqrt{45} } }  

                                    =  -2.68

The value of z-test statistics is -2.68.

<u>Now, the P-value of the test statistics is given by;</u>

         P-value = P(Z < -2.68) = 1 - P(Z \leq 2.68)

                      = 1- 0.99632 = 0.00368

For the two-tailed test, the P-value is calculated as = 2 \times 0.00368 = 0.00736.

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