It would most likely be 41 because when you would round 41 after you would × 41 times 10 equals 410 then you would round it to 400
<u>Given</u>:
Given that two lines are intersecting at the point.
The angles (3x - 8)° and (2x + 12)° are the angles formed by the intersection of the two lines.
We need to determine the equation to solve for x and the value of x.
<u>Equation:</u>
The two angles (3x - 8)° and (2x + 12)° are vertically opposite. Hence, the vertically opposite angles are always equal.
Hence, we have;
Hence, the equation is
<u>Value of x:</u>
The value of x can be determined by solving the equation
Thus, we have;
Subtracting both sides of the equation by 2x, we get;
Adding both sides of the equation by 8, we get;
Thus, the value of x is 20.
Hence, the equation and the value of x are 
Thus, Option D is the correct answer.
1.8x59 is 472
8(59)
2.9x84 is 756
9(84)
3.6x78 is 468
6(78)
4.7x96 is 672
7(96)
Answer:
he has received negative positive punishment...? I"M SORRY IF IT"S WRONG!!!
Step-by-step explanation:
This problem is asking you to apply the *Pythagorean Theorem*, given the information you’ve been given.
In case you’ve forgotten, the Pythagorean Theorem states that, in any given right triangle, the sum of the squares of the lengths of its legs is equal to the square of the length of its hypotenuse (the side opposite its right angle). If we call the lengths of the legs a and b, and the length of the hypotenuse c, this can be expressed in notation as a^2+b^2=c^2 (it doesn’t matter in this case which leg you pick for a and which you pick for b). Here, if we choose the left leg as a and the bottom leg as b, we’re given that a^2 (the area of a square with sides of length a) is 25 sq. in, and b is 3.5 in. Plugging those values into the equation, we have:
25 + (3.5)^2 = c^2
From here, you don’t even need to solve for c, you just need to find the value of c^2 (since you’re trying to find the area of a square with side lengths c). Just solve the left side of the equation, and you’ll have your answer in square inches.
