What is the area, in square inches, of the trapezoid below?

Write answer as an inequality solved for c

g100num [7]

He will spend at least $27. He has already spent $16

27-16=11

So, Henry will spend at least 11 more dollars

C ≥ 11

5 0

3 years ago

Jean and Jericho who are playing in the school grounds decided to sit on a

Natalija [7]

We want to see underline the correct part in each statement.

1) This situation illustrates (direct, inverse) variation.
2) The two quantities that must vary in this situation are (weight and 
distance from the center, height and weight).
3) The heavier the kid, the (closer, farther) he/she should be at the
center to balance the seesaw?
4) When Jean moves farther from the center, Jericho tends to go (up,
down).
5) If Jericho moves closer to the center, Jean tends to go (up, down).

So, Jean and Jericho are playing on a seesaw.

Jean is heavier than Jericho.

Now, notice that a seesaw is a lever. So it "amplificates" the force that you apply in one end to lift the weight that is on the other end. Depending on the form of the lever and the weights, the force that you need to do changes.

If we define:

W₁ = Jean's weight.
d₁ = Jean's distance to the center.
W₂ = Jericho's weight.
d₂ = Jericho's distance to the center.

We must have:

W₁*d₁ = W₂*d₂

Then:

1) This situation illustrates (direct, inverse) variation.

d₁, the position of Jean, varies inversely with respect to Jean's weight.

2) The two quantities that must vary in this situation are (weight and

distance from the center, height and weight).

(by the equation above)

3) The heavier the kid, the (closer, farther) he/she should be at the

center to balance the seesaw?

By the given equation, we see that d₁ must be smaller than d₂.

And the last two are trivial:

4) When Jean moves farther from the center, Jericho tends to go (up,

down).

5) If Jericho moves closer to the center, Jean tends to go (up, down).

If you want to learn more, you can read:

brainly.com/question/18320907

7 0

2 years ago

docker41 [41]

Given =

Two similar pyramid have base area of 12.2 cm² and 16 cm².

surface area of the larger pyramid = 56 cm²

find out the surface area of the smaller pyramid

To proof =

Let us assume that the surface area of the smaller pyramid be x.

as surface area of the larger pyramid is 56 cm²

Two similar pyramid have base area of 12.2 cm² and 16 cm².

by using ratio and proportion

we have

ratio of the base area of the pyramids : ratio of the surface area of the pyramids

$\frac{12.2}{16} : \frac{x}{56}$

x = 12.2 ×56× $\frac{1}{16}$

by solvingthe above terms

we get

x =42.7cm²

Hence the surface area of the smaller pyramid be 42.7cm²

Hence proved

3 0

3 years ago

Read 2 more answers

When dividing the polynomial using synthetic division, which of the following setup boxes would be used?

Galina-37 [17]

The setup boxes in the synthetic division are (b)

<h3>How to determine the setup boxes?</h3>

The dividend is given as:

x^3 + 4x^2 + x - 6

The divisor is given as:

x - 2

Set the divisor to 0

x - 2 = 0

Solve for x

x = 2

Remove the variables in the dividend

1 + 4 + 1 - 6

Remove the arithmetic signs

1 4 1 - 6

So, the setup is:

2 | 1 4 1 - 6

Hence, the setup boxes are (b)

Read more about synthetic division at:

brainly.com/question/12951962

#SPJ1

8 0

1 year ago

An ice cream store sells 28 flavors of ice cream. Determine the number of 4 dip sundaes.

katrin [286]

Answer:

$20,475\ ways$

Step-by-step explanation:

we know that

Combinations are a way to calculate the total outcomes of an event where order of the outcomes does not matter.

To calculate combinations, we will use the formula

$C(n,r)=\frac{n!}{r!(n-r)!}$

where

n represents the total number of items

r represents the number of items being chosen at a time.

In this problem

$n=28\\r=4$

substitute

$C(28,4)=\frac{28!}{4!(28-4)!}\\\\C(28,4)=\frac{28!}{4!(24)!}$

simplify

$C(28,4)=\frac{(28)(27)(26)(25)(24!)}{4!(24)!}$

$C(28,4)=\frac{(28)(27)(26)(25)}{(4)(3)(2)(1)}$

$C(28,4)=20,475\ ways$

5 0

3 years ago