$5 {w}^{2} - 5w = 0\Leftrightarrow 5w(w - 1) = 0\Leftrightarrow w = 0 \: \vee \: w = 1 \\ - 10 {n}^{2} + 35n = 0\Leftrightarrow - 5n(2n - 7) = 0\Leftrightarrow n = 0 \: \vee \: n = \frac{7}{2} \\ 2 {x}^{2} + 15x = 0\Leftrightarrow x(2x + 15) = 0\Leftrightarrow x = 0 \: \vee \: x = \frac{15}{2} \\ 18 {c}^{2} + 6c = 6c(3c + 1) = 0\Leftrightarrow c = 0 \: \vee \: c = - \frac{1}{3} \\ - 32 {y}^{2} - 24y = 0\Leftrightarrow - 8y(4y + 3) = 0\Leftrightarrow y = 0 \:\vee \: y = - \frac{3}{4} \\ 3 {k}^{2} = 6k\Leftrightarrow k = 0 \: \vee \: k = 2 \\ 6 {h}^{2} = 3h\Leftrightarrow h = 0 \: \vee \: h = \frac{1}{2} \\ 4 {s}^{2} = 10s\Leftrightarrow s = 0 \: \vee \: s = \frac{5}{2} \\ - 42 {z}^{2} = 14z\Leftrightarrow z = 0 \:\vee \: z = - \frac{1}{3}$

6 0

3 years ago

Estimate the solution to the following system.

tekilochka [14]

Answer:

(-150, 45)

Step-by-step explanation:

The solution to the system is where the two graphs intersect

My best guess from the graph is

(-150, 45)

5 0

3 years ago