3 years ago

The prefix "deka" is used to designate which power of ten? 21 9- ОООО 6 1

Physics

2 answers:

12345 [234]3 years ago

7 0

Answer:

1 is the power of ten.

Explanation:

$10^1$ is deka.

Basically 10 is deka, same result as $10^1$ .

eimsori [14]3 years ago

3 0

The prefix "deka" is used to designate which power of ten?

The prefix deka means the factor of ten or it represents ten raised to the power 1

$\mathfrak{ {10}^{1} }$

You might be interested in

When aluminum foil is formed into a loose ball, it can float on water. But when the ball of foil is pounded flat with a hammer,

docker41 [41]

Air caught in the ball of foil makes the ball less dense than water

8 0

3 years ago

The highest element in the hierarchical breakdown of the wbs is

Makovka662 [10]

Work package. Hope this helps!

5 0

3 years ago

What is the resulting velocity of the launcher if the net force on the launcher is equal to the reaction force?

xz_007 [3.2K]

Answer:

according to this question best answer is C

5 0

3 years ago

Which of the following can reduce biodiversity within a natural environment? A. Yucca moths pollinate and feed on yucca plants i

DaniilM [7]

I wanna say B Red-billed oxpeckers eat ticks off of impalas

8 0

3 years ago

A 25 kg block is held against a compressed spring and then the spring is allowed to decompress giving the block a velocity. The

Alex787 [66]

Answer:

h=18.05 cm

Explanation:

Given that

m= 25 kg

K= 1300 N/m

x=26.4 cm

θ= 19.5 ∘

When the block just leave the spring then the speed of block = v m/s

From energy conservation

$\dfrac{1}{2}Kx^2=\dfrac{1}{2}mv^2$

$Kx^2=mv^2$

$v=\sqrt{\dfrac{kx^2}{m}}$

By putting the values

$v=\sqrt{\dfrac{kx^2}{m}}$

$v=\sqrt{\dfrac{1300\times 0.264^2}{25}}$

v=1.9 m/s

When block reach at the maximum height(h) position then the final speed of the block will be zero.

We know that

$V_f^2=V_i^2-2gh$

By putting the values

$0^2=1.9^2-2\times 10\times h$

h=0.1805 m

h=18.05 cm

4 0

4 years ago