How thick a layer would Earth form as it wraps around the neutron star’s surface is: 6.67 10⁻³ m.
<h3>Density of the Neutron star</h3>
Density
ρ = m / V
Where:
ρ= density
m = mass of the planet 5.98 10²⁴ km
V =volume of the spherical layer
Volume of a sphere
Volume = 4/3 π r³
Mass = 1.5 = 1.5 1,991 10³⁰
Mass= 2.99 10³⁰ kg
Density:
ρ = 2.99 10³⁰ / [4/3 π (10 10³)³]
ρ is = 7.13 10 17 kg / m³
V = 5.98 10²⁴ / 7.13 10¹⁷
V = 8,387 10⁶ m³
Thickness of the layer
V = 4π r² e
e = V / 4π r
e = 8,387 10⁶ / [4π (10 10³)²]
e = 6.67 10⁻³ m
Inconclusion how thick a layer would Earth form as it wraps around the neutron star’s surface is: 6.67 10⁻³ m.
Learn more about Density of the Neutron star here:brainly.com/question/15700804
During the lunar<span> month, the </span>Moon<span> goes through all its </span>phases. You can see the phases<span> drawn in the image below. Just like the Earth, half of the </span>Moon<span> is lit by the Sun while the other half is in darkness. The </span>phases<span> we see result from the angle the </span>Moon<span> makes with the Sun as viewed from Earth.</span>
First, we want to solve for b.
In order to solve for b, we plug in x=6 and f(x)=7 into the equation, since we know f(6)=7
7 = (3/2)(6) + b
7 = 9 + b
Subtract both sides by 9
b = -2
Now, let's insert this value into the equation
f(x) = (3/2)x - 2
Now, plug in x = -2 into the equation to calculate f(-2)
f(-2) = (3/2)(-2) - 2
= -3 -2
= -5
Thus, your answer is A.
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