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Ksenya-84 [330]
2 years ago
7

-32/8 ill will mark as brain list

Mathematics
2 answers:
murzikaleks [220]2 years ago
5 0

Answer:

-4

Step-by-step explanation:

Elza [17]2 years ago
3 0
I think the answer is -4
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How do I prove that 2 cot 2x = cot x-tan x?
BlackZzzverrR [31]
We will start off working on the right hand side. 
<span>cot x - tan x </span>
<span>= [cos x / sin x] - [sin x / cos x] </span>
<span>= [(cos x)^ 2 - (sin x)^2] / [sin x cos x] </span>

<span>This is where it gets a bit tougher if you do not have your formula list with you. </span>
<span>(cos x)^ 2 - (sin x)^2 = cos(2x) </span>
<span>sin 2x = 2 sin x cos x </span>

<span>Note that by arranging the second formula, we will have sin x cos x = (1/2) sin 2x </span>

<span>Hence, we will get: </span>
<span>[(cos x)^ 2 - (sin x)^2] / [sin x cos x] </span>
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7 0
3 years ago
The graph of an equation with a negative discriminant always has which characteristic?
kobusy [5.1K]
No x intercept because there is no solution
4 0
2 years ago
What are the coordinates of the point on the directed line segment from (-6, -6)(−6,−6) to (9, -1)(9,−1) that partitions the seg
GrogVix [38]

Answer:

(0, -4)

Step-by-step explanation:

The coordinates of the points from which the directed line segment extends = (-6, -6) to (9, -1)

The ratio the required point partitions the line = 2 to 3

The formula for finding the coordinate of a point that partitions a line AB into a ratio 'a' to 'b', where the coordinates of, A = (x₁, y₁) and B = (x₂, y₂) is given as follows;

\left(\dfrac{a}{a + b} \times (x_1 - x_2)+ x_1, \ \dfrac{a}{a + b} \times (y_1 - y_2)+ y_1 \right)

Therefore, the required point is located as follows;

\left(\dfrac{2}{2 + 3} \times (9 - (-6))+ (-6), \ \dfrac{2}{2 + 3}\times (-1 - (-6))+ (-6) \right) = (0, -4)

The coordinates of the point is (0, -4)

6 0
3 years ago
Question
Goryan [66]

Given:

(2, 4) and (3, 3) are on the line.

To find:

The equation of line in point slope form.

Solution:

If a line passes through a point (x_1,y_1) with slope m, then the point slope form of the line is

y-y_1=m(x-x_1)

(2, 4) and (3, 3) are on the line. So, slope of the line is

m=\dfrac{y_2-y_1}{x_2-x_1}

m=\dfrac{3-4}{3-2}

m=\dfrac{-1}{1}

m=-1

The slope of a line is -1 and it passes through (2,4). So, an equation in point slope form is

y-4=-1(x-2)

Therefore, an equation of the line in point slope form is y-4=-1(x-2).

8 0
2 years ago
What is 49% of $201.13
Nookie1986 [14]

Answer:

98.5537

Step-by-step explanation:


8 0
3 years ago
Read 2 more answers
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