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kykrilka [37]
2 years ago
8

Rearrange the shaded letters to answer the following question.

Mathematics
1 answer:
Klio2033 [76]2 years ago
3 0

Answer:

Nice Belt is the correct answer

Step-by-step explanation:

I hope this helps

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20 POINTS<br> Can someone check over these? I have a quiz on it tomorrow :(
Mama L [17]

Looks good! You have the right answers.

However, the graph for 12 and 15 is inaccurate! Because he starts from a stop sign/stop light, the graph's speed should start from the origin!

Not to confuse you or anything, but this means the graph does not follow the description of the problem. Please let your teacher know so s/he can fix the worksheet.

3 0
3 years ago
Find the angle that makes them supplementary.
8090 [49]

Answer:

Mathematics NCERT Grade 7, Chapter 5: Lines and Angles is all about different lines, line segments, and angles.

A line segment has two end points.

A ray has only one end point (its vertex).

A line has no end points on either side.  

This chapter throws light on topics such as related angles, pair of lines. The chapter deals with different types of angles and lines. The types of angles discussed in this chapter are as follows:

Pairs of Angles          Condition

Two complementary angles Measures add up to 90°

Two supplementary angles Measures add up to 180°

Two adjacent angles Have a common vertex and a common arm but no common interior

Linear pair Adjacent and supplementary

A linear pair is a pair of adjacent angles whose non-common sides are opposite rays.

All the types are discussed in detail and are supplemented with examples and short questions.  

Under the topic pair of lines, various sub-sections are discussed namely:

Intersecting lines

Transversal  

Angles made by a transversal

When two lines intersect (looking like the letter X) we have two pairs of opposite angles. They are called vertically opposite angles. They are equal in measure.

A transversal is a line that intersects two or more lines at distinct points.

Six angles discussed in this section:

1. Interior angles

2. Exterior angles

3. Pairs of Corresponding angles

4. Pairs of Alternate interior angles

5. Pairs of Alternate exterior angles

6. Pairs of interior angles on the same side of the transversal

Transversal of parallel lines

5 0
3 years ago
The sign of the product of –35 and –625 is
Anarel [89]

Step-by-step explanation:

The mathematical sign for the operation is subtraction.

<em>To</em><em> </em><em>Solve</em><em> </em><em>This</em><em> </em><em>You</em><em> </em><em>Will</em><em> </em><em>Need</em><em> </em><em>To</em><em>;</em>

<em>1</em><em>]</em><em> </em><em>The</em><em> </em><em>sign</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>product</em><em> </em><em>of</em><em> </em><em>-</em><em>3</em><em>5</em><em> </em><em>and </em><em>-</em><em>6</em><em>2</em><em>5</em><em> </em><em>is</em><em>;</em>

<em>It's</em><em> </em><em>going </em><em>to</em><em> </em><em>be</em><em>;</em>

<em>-</em><em>3</em><em>5</em><em>-</em><em>-</em><em>6</em><em>2</em><em>5</em>

<em>The</em><em> </em><em>negative</em><em> </em><em>sign</em><em> </em><em>will</em><em> </em><em>turn</em><em> </em><em>into </em><em>addition </em><em>sign</em><em> </em><em>before </em><em>you </em><em>can </em><em>operate</em><em> </em><em>it</em><em>.</em><em> </em><em>So </em><em>it</em><em>'s</em><em> </em><em>going</em><em> </em><em>to </em><em>be</em><em>;</em>

<em>-</em><em>3</em><em>5</em><em>+</em><em>6</em><em>2</em><em>5</em><em>=</em><em>5</em><em>9</em><em>0</em><em>(</em><em>positive</em><em>)</em>

<em>It's</em><em> </em><em>just</em><em> </em><em>like</em><em> </em><em>subtracting </em><em>3</em><em>5</em><em> </em><em>from</em><em> </em><em>6</em><em>2</em><em>5</em><em>.</em>

<em>2</em><em>]</em><em> </em><em>The </em><em>sign</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>product</em><em> </em><em>of </em><em>2</em><em>6</em><em>3</em><em> </em><em>and</em><em> </em><em>0</em><em> </em><em>is</em><em>;</em>

<em>2</em><em>6</em><em>3</em><em>-</em><em>0</em>

<em>With </em><em>this</em><em> </em><em>no</em><em> </em><em>qua</em><em>n</em><em>t</em><em>i</em><em>t</em><em>y</em><em> </em><em>is</em><em> </em><em>going</em><em> </em><em>to</em><em> </em><em>be</em><em> </em><em>subtracted </em><em>so</em><em> </em><em>the</em><em> </em><em>2</em><em>6</em><em>3</em><em> </em><em>will</em><em> </em><em>remain</em><em> </em><em>the</em><em> </em><em>same</em><em>.</em><em> </em>

<em>So</em><em> </em><em>2</em><em>6</em><em>3</em><em>-</em><em>0</em><em>=</em><em>2</em><em>6</em><em>3</em><em>(</em><em>positive</em><em>)</em>

<em>3</em><em>]</em><em> </em><em>The</em><em> </em><em>sign</em><em> </em><em>of </em><em>the</em><em> </em><em>product</em><em> </em><em>of</em><em> </em><em>-</em><em>2</em><em>1</em><em> </em><em>and</em><em> </em><em>4</em><em>5</em><em>1</em><em> </em><em>is</em><em>;</em>

<em>-</em><em>2</em><em>1</em><em>-</em><em>4</em><em>5</em><em>1</em>

<em>With </em><em>this</em><em> </em><em>you </em><em>won't</em><em> </em><em>subtract</em><em> </em><em>but</em><em> </em><em>rather</em><em> </em><em>you'll</em><em> </em><em>add</em><em> </em><em>and</em><em> </em><em>when</em><em> </em><em>you</em><em> </em><em>add</em><em> </em><em>the</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>going </em><em>to</em><em> </em><em>be</em><em> </em><em>-</em><em>4</em><em>7</em><em>2</em>

<em>-</em><em>4</em><em>7</em><em>2</em><em>(</em><em>negative</em><em>)</em>

<em>4</em><em>]</em><em> </em><em>The</em><em> </em><em>sign </em><em>of</em><em> </em><em>the</em><em> </em><em>product </em><em>of</em><em> </em><em>-</em><em>3</em><em>5</em><em>0</em><em> </em><em>and</em><em> </em><em>8</em><em>9</em><em> </em><em>is</em><em>;</em>

<em>-</em><em>3</em><em>5</em><em>0</em><em>-</em><em>8</em><em>9</em>

<em>With </em><em>this</em><em> </em><em>you</em><em> </em><em>will</em><em> </em><em>add</em><em> </em><em>it</em><em> </em><em>but</em><em> </em><em>you </em><em>won't</em><em> </em><em>subtract</em><em> </em><em>the</em><em> </em><em>negatives </em><em>so</em><em> </em><em>it's</em><em> </em><em>going</em><em> </em><em>to </em><em>be</em><em>;</em>

<em>-</em><em>3</em><em>5</em><em>0</em><em>-</em><em>8</em><em>9</em><em>=</em><em>-</em><em>4</em><em>3</em><em>9</em><em>(</em><em>negative</em><em>)</em>

<em>Hope </em><em>I</em><em> </em><em>am</em><em> </em><em>Correct </em><em>I</em><em> </em><em>didn't</em><em> </em><em>really</em><em> </em><em>understand</em><em> </em><em>your</em><em> </em><em>question</em><em> </em><em>well</em><em>.</em><em> </em><em>But</em><em> </em><em>Good</em><em> </em><em>Luck</em><em>:</em><em>)</em>

3 0
3 years ago
Read 2 more answers
Bailey's rectangular dog pen for his Irish Setter must have an area of 400 square feet. Also, the length must be 20 feet longer
Iteru [2.4K]
Hello.


400=(x+20)x is the equation or 400=x^2+20x 


<span>(x+10)=square root of 500 
</span>

<span>so x+10=10 radical 5 
</span>


<span>final answer -10 + or - 10 radical 5=x 
</span>

Have a nice day
8 0
3 years ago
A pair of $36 jeans were on sale at Jim's Jeans for 1/3 off. The same pair of jeans were $42 at David's Denims. The jeans were o
nikklg [1K]

Complete question :

A pair of $36 jeans were on sale at Jim's Jeans for 1/3 off. The same pair of jeans were $42 at David's Denims. The jeans were on sale for 2/3 off.

A.) which store had the better buy

B.) how much will you pay at the store that has the better buy

Answer:

A.)David's denim has the better buy

B.) $14

Step-by-step explanation:

Jim's Jean store :

Cost of Jean = $36

Discount = 1/3 off

Discounted cost = $36 - (1/3 * $36)

Discounted cost = $36 - $12 = $24

David's Denim:

Cost of Jean = $42

Discount = 2/3 off

Discounted cost = $42 - (2/3 * $42)

Discounted cost = $42 - $28 = $14

David's denim has the better buy with a discounted price lower than the discounted price at Jim's store.

Cost at store with the better buy is $14

8 0
3 years ago
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