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m_a_m_a [10]
3 years ago
10

Classify the model as Exponential GROWTH or DECAY. A=10(1.01)^3

Mathematics
1 answer:
Masteriza [31]3 years ago
5 0

Answer:

GROWTH

Step-by-step explanation:

Given the Exponential function;

A=10*1.01^{3}

As we can see in the given function above:

the base number is 1.01 which is greater than 1 hence the quantity increases,

slowly at first and then very rapidly over its domain. The rate of growth becomes faster as time passes.

The growth "rate" (r) is determined as b = 1 + r.

In this situation, the rate growth is = 1.01 -1  = 0.01

Hope it will find you well.

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The volume of a cube is 124 cubic inches.<br> What is the side length of the cube?
ivolga24 [154]

Answer:

4.987 in

Step-by-step explanation:

Volume of a cube=  (where x= side)

x³

we know that

124=x³

∛124=x

x=4.986630952 which rounds to

4.987

8 0
3 years ago
Read 2 more answers
Based on the graph, what does (1,3) represent ?
san4es73 [151]

Answer:

The correct answer should be B.

I hope this helps!

-Mikayla

4 0
3 years ago
Find the slope of the line going through the points (-5, 2) and (-1,5).
Karolina [17]
The slope would be 3/4 because 5 - 2 is 3 and -1 - (-5) is 4. Hope this helps!
4 0
2 years ago
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Solve the integral:<br><img src="https://tex.z-dn.net/?f=%20%5Cint%20%5C%3A%20%20%7Be%7D%5E%7B%20-%20%20%7Bx%7D%5E%7B2%7D%20%7D%
Sever21 [200]

e^{-x^2} has no antiderivative in terms of elementary functions (polynomials, exponentials, logarithms, trigonometric functions, etc), but there is a special function defined to fit that role called the error function, \mathrm{erf}(x), where

\mathrm{erf}(x)=\displaystyle\frac2{\sqrt\pi}\int_0^xe^{-t^2}\,\mathrm dt

By the fundamental theorem of calculus, we can see that

\dfrac{\mathrm d}{\mathrm dx}\mathrm{erf}(x)=\dfrac2{\sqrt\pi}e^{-x^2}

which means we have

\displaystyle\int e^{-x^2}\,\mathrm dx=\dfrac{\sqrt\pi}2\mathrm{erf}(x)+C

8 0
3 years ago
If two objects travel through space along two different curves, it’s often important to know whether they will collide. (Will a
galina1969 [7]

Answer:

<em>Both objects collide at t=3 in the point  <9,9,9></em>

Step-by-step explanation:

<em>Collision Of Moving Objects </em>

Two objects can describe different trajectories in the space. Those trajectories can intersect in one or more points but it doesn't mean they collide. Collision occurs if they are in the same position at the same time. If we know the positions as a function of time of each object, we could try so find if, for a given time, they are in the same position.

The positions of two object are given as

r1(t)=

r2(t)=

Let's find out if there is at least one value of t that makes both positions to be the same. We can try by equating one of the three coordinates and testing if the value of t make both have the same x,y,z coordinate. Let's try equating the x-components of both

t^2=4t-3

Rearranging

t^2-4t+3=0

Factoring

(t-1)(t-3)=0

We found two solutions

t=1,\ t=3

for t=1 the x-coordinates are

x1=t^2=1

x2=4t-3=1

For t=3

x1=t^2=9

x2=4t-3=9

Now we'll test both values in the y-coordinates

y1=7t-12

y2=t^2

For t=1

y1=-5

y2=1

Thus they don't collide at t=1. Let's try t=3

y1=7(3)-12=9

y2=3^2=9

Now let's try the z-coordinate for t=3

z1=t^2=9

z2=5t-6=9

Since the three coordinates match, we can say both objects collide at t=3 in the point  <9,9,9>

6 0
3 years ago
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