Answer
The answer and procedures of the exercise are attached in the following archives.
Step-by-step explanation:
You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.
40 adult tickets were sold and 35 children tickets were sold
<em><u>Solution:</u></em>
Let "a" be the number of adult tickets sold
Let "c" be the number of children tickets sold
Cost of 1 adult ticket = $ 8
Cost of 1 children ticket = $ 5
<em><u>Given that April sold 75 tickets to the school Christmas play and collected $495</u></em>
Number of tickets sold = 75
number of adult tickets sold + number of children tickets sold = 75
a + c = 75 ----- eqn 1
<em><u>Given that April collected $495</u></em>
Thus we can frame a equation as:
number of adult tickets sold x Cost of 1 adult ticket + number of children tickets sold x Cost of 1 children ticket = $ 495
8a + 5c = 495 ----- eqn 2
<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "c"</u></em>
From eqn 1,
a = 75 - c ---- eqn 3
Substitute eqn 3 in eqn 2
8(75 - c) + 5c = 495
600 - 8c + 5c = 495
-3c = 495 - 600
-3c = - 105
<h3>c = 35</h3>Substitute c = 35 in eqn 3
a = 75 - 35
<h3>a = 40</h3>Thus 40 adult tickets were sold and 35 children tickets were sold
Answer: a) 0.545,b) 0.41, c) 0.045, d) not possible.
Step-by-step explanation:
The Sky Ranch is a supplier of aircraft parts. Included in stock are 10 altimeters that are correctly calibrated and two that are not. Three altimeters are randomly selected without replacement. Let the random variable
x represent the number that are not correctly calibrated.
Complete the probability distribution table.
x={0,1,2,3}
P(x=0)=?
P(x=1)=?
P(x=2)=?
P(x=3)=?
Since we have given that
n = 12
number of good one = 3 from 10
number of bad one = 2
So, P(X=0)=
P(X=1) =
P(X=2)=
P(X=3) is not possible.
Hence, a) 0.545,b) 0.41, c) 0.045, d) not possible.