Answer:
8.20in³
Step-by-step explanation:
Given V = πr²h
r is the radius = 1.5in
h is the height = 6in
thickness of wall of the cylinder dr = 0.04in
top and bottom thickness dh 0.07in+0.07in = 0.14in
To compute the volume, we will find the value of dV
dV = dV/dr • dr + dV/dh • dh
dV/dr = 2πrh
dV/dh = πr²
dV = 2πrh dr + πr² dh
Substituting the values into the formula
dV = 2π(1.5)(6)•(0.04) + π(1.5)²(6) • 0.14
dV = 2π (0.36)+π(1.89)
dV = 0.72π+1.89π
dV = 2.61π
dV = 2.61(3.14)
dV = 8.1954in³
Hence volume, in cubic inches, of metal in the walls and top and bottom of the can is 8.20in³ (to two dp)
Hello!
Angles CAD and EAB are congruent.
The reason why is that they are vertical angles. Their points meet and therefore they are congruent.
I hope this helps!
6/20 = 3/10 = 12/40
I got 3/20 by dividing 6/20 by 2/2 and 12/40 by multiplying 6/20 by 2/2. You can make fractions <span>equivalent</span> by multiplying the numerator and denominator by the same number
Hmmm.... i would help but im confused with this one ahhh i need help with my hw right now but idk what the answer are ugh
