Answer:
Rotation.
Step-by-step explanation:
There are three rigid motions (which do not change the shape and size of the figures): rotation, translation and reflection.
You make a rotation of a figure when you turn it about a fixed point (which can be inside, on an edge or outside the figure) and it is measured in degrees. The rotation can be clockwise or counterclockwise.
Answer:
y=3
y=1
y=0
Step-by-step explanation:
Answer:
A sample size of 6755 or higher would be appropriate.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
The margin of error M is given by:
90% confidence level
So , z is the value of Z that has a pvalue of , so .
52% of Independents in the sample opposed the public option.
This means that
If we wanted to estimate this number to within 1% with 90% confidence, what would be an appropriate sample size?
Sample size of size n or higher when . So
A sample size of 6755 or higher would be appropriate.
Answer:
<-8.60, -12.29>
Step-by-step explanation:
Pictuas shown in the attached image to represent the direction 35 west of south of the vector velocity and understand which trig function to use for its components. See the actual vector velocity as the hypotenuse of a right angle triangle.
The vertical component would be pointing down, and its magnitude would result from the use of the cosine of the angle (since it involves the adjacent side to the angle):
15 * cos (35) = 12.29
the horizontal component is pointing left, and its magnitude would be the result of the use of the sine of the angle (it involves the opposite side to the angle):
15 * (sin*35) = 8.60.
Using the fact that the components are pointing down and pointing left, we need to include a negative sign to both.
Therefore the component form of the vector is: <-8.60, -12.29>
we can simply put both fractions with the same denominator, and thus then we can just compare which numerator is larger.
we can do so by <u>multiplying each fraction by the other's denominator</u>, let's proceed.