If a apple tree has 200 apples and some one takes half how much would there be left

Can somebody help me please.

Fofino [41]

Answer:

x intercept = (0.3, 0)

y intercept = (0, 0.4)

3 0

3 years ago

Read 2 more answers

Write the following number by entering one digit in each box of the place value chart.

ratelena [41]

Answer:

see the attached

Step-by-step explanation:

Each digit goes in the place corresponding to its place value.

When no digit has a given place value, a placeholder is used. That is the purpose of zero, a great invention in the history of mathematics. It makes place-value number systems possible.

8 0

3 years ago

a school netball team won ten matches , lost four and drew 1/8 of the total played . how many matches were drawn and what fracti

defon

The school net ball team drew 2 matches. The team won $\frac{5}{8}$ of total matches played

<h3>Solution:</h3>

Given, A school netball team won ten matches, lost four and drew $\frac{1}{8}$ of the total played

Let the total number of matches played be "n"

Number of matches drawn = $\frac{1}{8}$ of n

Total matches played = number of won matches + number of lost matches + number of drawn matches

$\begin{array}{l}{n=10+4+\frac{1}{8} n} \\\\ {n-\frac{1}{8} n=10+4}\end{array}$

Taking "n" as common from left hand side,

$\begin{array}{l}{\mathrm{n}\left(1-\frac{1}{8}\right)=14} \\\\ {\mathrm{n} \times \frac{8-1}{8} \quad 14} \\\\ {\mathrm{n} \times \frac{7}{8}=14} \\\\ {\mathrm{n}=16}\end{array}$

So, they played 16 matches in total

Number of matches drawn = $\frac{1}{8}$ of n = $\frac{1}{8} \times 16 = 2$ $\text { Fraction of won matches }=\frac{\text { number of matches won }}{\text { number of matches played }}=\frac{10}{16}=\frac{5}{8}$

$\text { Hence, the team drew } 2 \text { matches and won } \frac{5}{8} \text { of total played matches. }$

3 0

3 years ago

frans furniture company charges $0.75 per pound to ship furniture. Write an equation to determine the total cost, c, to ship p p

Rina8888 [55]

The first equation is, 0.75 p=c. 0.75 (223) = 167.25. The equation with the reduced cost is 0.65 p=c.

7 0

3 years ago

The probability a household in a community uses gas for cooking is 0.18. If a shopper from the community is from a household tha

Lyrx [107]

Answer:

The probability of a person from the community not shopping at Prime Foods given that he uses gas for cooking at his household is 0.092

Step-by-step explanation:

Hello!

Given the information:

A: "The household uses gas for cooking" ⇒ P(A)= 0.18

B: "The person from the comunity shops at Prime Foods"

The person shops at Prime Foods given that he uses gas for cooking:

P(B/A)= 0.7

The person shops at Prime Foods given that he doesn't use gas for cooking:

P(B/Ac)= 0.35

If the person doesn't shop at Prime Foods, what is the probability that he uses gas for cooking?

Symbolically:

P(A/Bc) = P(A∩Bc)

P(Bc)

The event Bc is the complement of event B, so it's probability is P(Bc)= 1 - P(B)

You can calculate the probability of B as:

P(B)= P(A∩B)+ P(Ac∩B)

Using the information of P(B/A)= 0.7 and P(B/Ac)= 0.35 you can reach the values of both intersections.

P(B/A)= P(A∩B)

P(A)

P(B/A)*P(A)= P(A∩B)

P(A∩B)= 0.7*0.18= 0.126

and

P(B/Ac)= P(Ac∩B)

P(Ac)

If A and Ac are complementary events, then P(Ac)= 1 - P(A)= 1 - 0.18= 0.82

Then:

P(B/Ac)*P(Ac)= P(Ac∩B)

P(Ac∩B)= 0.35*0.82= 0.287

The probability of B is:

P(B)= P(A∩B)+ P(Ac∩B)= 0.126+0.287= 0.413

P(Bc)= 1 - P(B)= 1 - 0.413= 0.587

And

P(A)= P(A∩B)+P(A∩Bc)

P(A∩Bc)=P(A)=-(A∩B)= 0.18-0.126= 0.054

Finally:

P(A/Bc) = P(A∩Bc) =0.054 = 0.0919≅ 0.092

P(Bc) 0.587

I hope it helps!

4 0

3 years ago