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3 years ago

Can somebody help me please.

Mathematics

2 answers:

yaroslaw [1]3 years ago

7 0

Answer:

x: (0.3,0)

y: (0,0.4)

Fofino [41]3 years ago

3 0

Answer:

x intercept = (0.3, 0)

y intercept = (0, 0.4)

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Please help!! I'll give brainliest and everything else!

FromTheMoon [43]

Answer:

the third one down

Step-by-step explanation:

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3 years ago

I WILL GIVE BRAINLIEST!!!

andre [41]

Answer:

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Step-by-step explanation:

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3 years ago

And algebra teacher drove by a farm yard full of chickens and pigs. The teacher happened to notice there were total of 70 heads

Oksanka [162]

To solve this problem, we are going to use a system of equations. Let the variable c represent the number of chickens in the farm yard and the variable p represent the number of pigs in the farm yard. If there is a total of 70 heads, this means that the total number of animals (chickens plus pigs) must be 70. This can be represent by the equation: c + p = 70. We are also told that there are 200 legs. Using our knowledge that chickens have 2 legs and pigs have 4 legs, we can construct the following equation: 2c + 4p = 200. Our system of equations is as follows:

c + p = 70

2c + 4p = 200

To solve, we are going to subtract c from both sides of the first equation so that we can get the variable p alone. Then, using this value for p in terms of c, we are going to substitute into the second equation. This method is shown below:

c + p = 70

p = 70 - c

2c + 4p = 200

2c + 4(70-c) = 200

To solve this equation, we are first going to distribute the coefficient of 4 through the parentheses on the left side of the equation to simplify.

2c + 280 - 4c = 200

Next, we are going to combine like terms on the left side of the equation. This means adding together the two terms that both have a variable c.

-2c + 280 = 200

Next, we are going to subtract 280 from both sides of the equation so that we can move all of the constant (number only) terms to the right side of the equation.

-2c = -80

Finally, we are going to divide both sides of the equation by -2 to get the variable c alone.

c = 40

We should now substitute this value for c back into one of our original equations to solve for p.

c + p = 70

40 + p = 70

To solve, simply subtract 40 from both sides of the equation to get the variable p alone.

p = 30

Therefore, your answer is that there were 40 chickens and 30 pigs.

Hope this helps!

7 0

3 years ago

Find the simplest pattern and insert the missing term(s) of each sequence. 33, 39, 51, 57, 69, 84, ____

Vadim26 [7]

Answer:

Step-by-step explanation:

Such "find a pattern" problems can always be answered a number of ways.

Here, the alternating pattern (6, 12, 6, 12, ...) of first differences doesn't seem to hold. However, the first differences of alternate terms does seem to be constant: 33, 51, 69 all have a common difference of 18.

The next term in that sequence is 69+18 = 87.

___

The other terms seem to have increasing differences:

57 -39 = 18

84 -57 = 27

If that pattern continues, then the second missing term will be 84 +36 = 120.

___

So, one way to extend the sequence is ...

33, 39, 51, 57, 69, 84, 87, 120, 105, 165, ...

The rule is that the sequence alternates a linear sequence and a quadratic one.

6 0

3 years ago

Question is down below

777dan777 [17]

Answer:

the correct answer is option ( D )

Step-by-step explanation:

hope it helps

ALONE96

7 0

2 years ago

Read 2 more answers

Can somebody help me please.​

Can somebody help me please.