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diamong [38]
3 years ago
10

A six-sided number cube is rolled 900 times.

Mathematics
2 answers:
hram777 [196]3 years ago
8 0

It is expected that a number greater than 4 will be rolled 300 times

The sample space of a die is:

S = {1,2,3,4,5,6}

The probability of obtaining a number greater than 4 is:

p = 2/6

p = 1/3

In 900 rolls, the expected number of number greater than 4 is:

E(x) = p *n

This gives

E(x) = 1/3 *900

E(x) =300

Hence, it is expected that a number greater than 4 will be rolled 300 times

Read more about expected values at:

brainly.com/question/15858152

stepan [7]3 years ago
5 0

Answer: Rolling a die and obtaining a number follows a binomial distribution.

Expected value of binomial distribution is

E[X]=np

where n is number of toss and p is probability of obtaining the number.

Therefore here the expected value of obtaining a number 4 is:

E[X]=900∗16=150

Step-by-step explanation:

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