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hoa [83]
3 years ago
15

Simplify the algebraic expression: 5 + 3(2y - 4) - 11y

Mathematics
2 answers:
dusya [7]3 years ago
6 0

Answer:

-5y -7

Step-by-step explanation:

expand: 3(2y-4):   6y-12 = 5+6y-12-11y        

simplify: 5+6y -12-11y:      -5y-7

answer: -5y-7

Iteru [2.4K]3 years ago
3 0

5 + 6  − 1 2 − 1 1  -11y 5+6y−12−11y − 7 + 6  − 1 1  

− 7 + 6  − 1 1   −7+6y−11y − 7 − 5  

− 7 − 5  −7−5y − 5  − 7

Solution: −5y−7

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Which of the following numbers is rational but not an integer <br> A.0<br> B.3<br> C.-9<br> D.-4.3
Mashutka [201]

Answer:

Thus, every integer is a rational number. Clearly, 3/2,-5/3, etc. are rational numbers but they are not integers. Hence, every integer is a rational number but a rational number need not be an integer.

Step-by-step explanation:

7 0
3 years ago
2<br> 3<br> h<br> =<br> 4<br> need answer asap
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Answer:

h=4/23

Step-by-step explanation:

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Mark all the relative minimum points in the graph.
creativ13 [48]

Answer:

Step-by-step explanation:

The thing to remember is that absolute can be relative but relative can't be absolute. In other words, absolute min is the very lowest point on the graph and there's usually only one (unless there are 2 absolute mins that have the same y value) while relative mins can occur at several points on a graph. That means that the only relative min point on the graph occurs at (-3, 4); the absolute min occurs at (5, -6).

5 0
3 years ago
A new building is being constructed at UT Austin. It is 200 feet tall, and has a
Mariana [72]

Answer:

Walkway is 3 feet wide.

Step-by-step explanation:

Given:

Length of the building is 150 ft

width of the building is 100 ft

walkway is x ft wide.

Total area(around and including the building) = 16536 square feet

Solution:

Length of the total area will be = length of the building + width of walkway from 2 sides = 150 +2x

Width of the total area will be = width of the building + width of walkway from 2 sides = 100 +2x

Now Total area(around and including the building) = Length of the total area\times Width of the total area

(150+2x)\times(100+2x)=16536\\15000+300x+200x+4x^2=16536\\500x+4x^2=16536-15000\\4(125x+x^2)=1536\\125x+x^2= \frac{1536}{4}=384\\

x^2+125x-384=0\\x^2-3x+128x-384=0\\x(x-3)+128(x-3)=0\\(x-3)(x+128)=0\\

Now solving for both equation we get.

x+128=0\\x=-128\\x-3=0\\x=3

Now, We get 2 values for x which -128 and 3 but the width of the building can't be in negative value hence we will consider value of x be 3.

∴ Width of the walkway is 3 ft.

4 0
3 years ago
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