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antiseptic1488 [7]
3 years ago
8

How do I solve this? I need help

Mathematics
1 answer:
Sedaia [141]3 years ago
7 0
Answer: √51
—————————
a^2 + b^2 = c^2
a^2 + 7^2 = 10^2
a^2 + 49 = 100
a^2 = 51
√(a^2) = √51
a = √51
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The length of the batter's box on a softball field is 1 ft more than twice the width. The area of the batter's box is 78 ft2. Fi
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The length and width of the rectangular box are 13 ft and 6 ft respectively.

<h3>How to find the length and width of a rectangle?</h3>

The length of the batter's box on a softball field is 1 ft more than twice the width.

The area of the batter's box is 78 ft².

The length and width of the rectangular batter's box can be found as follows:

Therefore,

area of a rectangle = lw

where

  • l = length
  • w = width

Therefore,

area of the rectangular box = 78 ft²

l = 1 + 2w

Hence,

78 = (1 + 2w)w

78 = w + 2w²

2w² + w - 78 = 0

Hence,

w = 6  and w =  -13  /2

we can only use positive values.

Therefore,

width = 6 ft

length  = 2(6) + 1 = 13 ft

learn more on rectangle here: brainly.com/question/14537807

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4 years ago
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