Hi! i think it’s d, just by process of elimination!! it cant be any of the others, and d estimates to be right.
Answer:
compare the distance between the lines at one point to the distance between the lines at another point
Step-by-step explanation:
You can construct perpendiculars at different points and compare the distance between the lines at those perpendiculars. The distance between parallel lines is the same everywhere.
2L +2W=160
100+ 2W=160
subtract 100 from each side
2W=60
divide by two each side
W=30
use the formula L×W=Area or 50×30 which equals 150 the are of the pasture is 150 feet²
Answer: I don’t actually know sorry
Step-by-step explanation:
Answer:
68% of jazz CDs play between 45 and 59 minutes.
Step-by-step explanation:
<u>The correct question is:</u> The playing time X of jazz CDs has the normal distribution with mean 52 and standard deviation 7; N(52, 7).
According to the 68-95-99.7 rule, what percentage of jazz CDs play between 45 and 59 minutes?
Let X = <u>playing time of jazz CDs</u>
SO, X ~ Normal(
)
The z-score probability distribution for the normal distribution is given by;
Z =
~ N(0,1)
Now, according to the 68-95-99.7 rule, it is stated that;
- 68% of the data values lie within one standard deviation points from the mean.
- 95% of the data values lie within two standard deviation points from the mean.
- 99.7% of the data values lie within three standard deviation points from the mean.
Here, we have to find the percentage of jazz CDs play between 45 and 59 minutes;
For 45 minutes, z-score is =
= -1
For 59 minutes, z-score is =
= 1
This means that our data values lie within 1 standard deviation points, so it is stated that 68% of jazz CDs play between 45 and 59 minutes.