Using the binomial distribution, it is found that there is a 0.5 = 50% probability of selecting a two-child family with one boy and one girl.
For each child, there are only two possible outcomes, either it is a boy, or it is a girl. The probability of a child being a boy or being a girl is independent of any other child, which means that the binomial distribution is used to solve this question.
Binomial probability distribution
The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem:
- Two children, hence .
- Equally as likely to be a boy or a girl, hence .
The probability of one of each is P(X = 1), hence:
0.5 = 50% probability of selecting a two-child family with one boy and one girl.
A similar problem is given at brainly.com/question/24863377
Answer:
I think its the last one thats not showing if I'm wrong in sorry
Answer:
3.8
Step-by-step explanation:
solution are in the pics
Answer:
$36.00
Step-by-step explanation:
The formula for simple interest is I = P x r x t where P is the principal amount, $600.00, r is the interest rate, 2% per year, or in decimal form, 2/100=0.02, and t is the time involved, 3....year(s) time periods. So t is 3....year time periods. To find the simple interest, we multiply 600 × 0.02 × 3 to get that the interest is $36.00 . Usually now, the interest is added onto the principal to figure some new amount after 3 year(s), or 600.00 + 36.00 = 636.00.