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ELEN [110]
3 years ago
8

Use the pattern of the rate of change to complete the table below that represents a

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
8 0
Since it is a linear function, the rate on change will be constant. Every time the x value goes down by 1, the y goes down by 3 so when x is 2 y is -4 and when x is 3 y is -7.
You might be interested in
Help please!!!!!!!!!
Triss [41]
The answer is -4, hope this helped
8 0
3 years ago
Jacksons fotball team won 70%of the games that they played.if they won 14 games how many total games did they play
Luden [163]

Answer:

20 gmaes in all

Step-by-step explanation:

14/x = 70%

x = 14/70%

4 0
3 years ago
Quadrilateral ABCD ​ is inscribed in a circle.
Lerok [7]
In general, the sum of the measures of the interior angles of a quadrilateral is 360. This is true for every quadrilateral. This does not help here, because there are two angles (angles B and D) we know nothing about. We only know about opposite angles A and C.

In this case, you can use another theorem.
Opposite angles of an inscribed quadrilateral are supplementary.

m<A + m<C = 180

3x + 6 + x + 2 = 180

4x + 8 = 180

4x = 172

x = 43

m<A = 3x + 6 = 3(43) + 6 = 135

Answer: 135 deg
6 0
2 years ago
What are the approximate values of the minimum and maximum points of f(x) = x5 − 10x3 + 9x on [-3,3]?
nika2105 [10]

Answer:

Minimum : -37 at x=2.4 and

Maximum = 37 at x=-2.4.

Step-by-step explanation:

Given:

f(x)=x^5-10x^3+9x; [-3,3]

Explanation:

In order to find minimum/maximum of a function, we need to find the first derivative of the function and then set it equal to 0 to get critical points.

Therefore,

f'(x)=5x^4-30x^2+9

Setting derivative equal to 0, we get

5x^4-30x^2+9=0

On applying quadratic formula, we get

x=2.4, -2.4, -0.7, 0.7.

So, those are critical points of the given function.

Plugging the values x=2.4, -2.4, -0.7, 0.7, -3 and 3 in above function, we get

f(2.4)=(2.4)^5-10(2.4)^3+9(2.4)= -37.01376   : Minimum.

f(-2.4)=(-2.4)^5-10(-2.4)^3+9(-2.4)= 37.01376 : Maximum.

f(0.7)=(0.7)^5-10(0.7)^3+9(0.7) = 3.03807

f(-0.7)=(-0.7)^5-10(-0.7)^3+9(-0.7) = -3.03807

f(-3)=(-3)^5-10(-3)^3+9(-3) =0

f(3)=(3)^5-10(3)^3+9(3) =0

Therefore the approximate values of the minimum and maximum points of f(x) = x^5- 10x^3+ 9x on [-3,3] are:

Minimum : -37 at x=2.4 and

Maximum = 37 at x=-2.4.


7 0
3 years ago
Apples are $2.49/pound. You need 2.5 pounds to make apple crisp. How much will you spend on apple in total? Show your work for f
Sedbober [7]

Answer:

2.5 is the answer

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
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