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kompoz [17]
3 years ago
5

Perform the indicated operation:

Mathematics
1 answer:
yaroslaw [1]3 years ago
7 0

The expression \frac{m^{2}-16\cdot n^{2}}{\frac{3\cdot m + 12\cdot n}{m\cdot n} } is equal to \frac{m^{2}\cdot n}{3} -\frac{4\cdot m\cdot n^{2}}{3}.

<h3>How to simplify a composite algebraic expression</h3>

In this question we must use properties of <em>real</em> algebra to simplify a given expression as most as possible. We proceed to show each step with respective reason.

  1. \frac{m^{2}-16\cdot n^{2}}{\frac{3\cdot m + 12\cdot n}{m\cdot n} }  Given
  2. \frac{m\cdot n \cdot (m^{2}-16\cdot n^{2})}{3\cdot m + 12\cdot n}   \frac{\frac{a}{b} }{\frac{c}{d} } = \frac{a\cdot d}{c\cdot b}
  3. \frac{m\cdot n \cdot (m-4\cdot n)\cdot (m+4\cdot n)}{3\cdot (m+4\cdot n)} Distributive property/a^{2}-b^{2} = (a +b)\cdot (a-b)
  4. \frac{m\cdot n \cdot (m-4\cdot n)}{3} Existence of the multiplicative inverse/Modulative property
  5. \frac{m^{2}\cdot n}{3} -\frac{4\cdot m\cdot n^{2}}{3} Distributive property/x^a\cdot x^{b} = x^{a+b}/Result

To learn more on algebraic expressions, we kindly invite to check this verified question: brainly.com/question/953809

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Step-by-step explanation:

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3 years ago
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What's 221 rounded to the nearest 10
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3 years ago
g Let G be a not necessarily abelian group with normal subgroups H and K such that H contains K (i.e., K ✂ G, H ✂ G, K ≤ H) and
allsm [11]

Answer:

Lets a,b be elements of G. since G/K is abelian, then there exists k ∈ K such that ab * k = ba (because the class of ab, [ab]_K is equal to [ba]_K, thus ab and ba are equal or you can obtain one from the other by multiplying by an element of K.

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4 0
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ipn [44]

Answer:

B 137.32 cm³

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Simply take the original cost and multiply it by the percentage to get the tip amount then add it all together.

14 × 15% = 2.1

14 + 2.1 = 16.1

This means the haircut would cost a total of $16.10.

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