Ask question

Ask question

All categories

3 years ago

15

1) Is 11 an irrational number? yes no Submit Yea

1 answer:

slamgirl [31]3 years ago

5 0

Answer:

YES

Step-by-step explanation:

Most real numbers (points on the number-line) are irrational (not rational). The rational numbers are those which have repeating decimal expansions (for example 1/11=0.09090909..., and 1=1.000000...=0.999999...) . They are also those which have terminating continued fraction expansions.

You might be interested in

Mistery number . CLUES: -it has the digits 8,5 and 6 . - it is a odd number . - it has 8 in the hundreds place . WHAT IS THE MIS

Ipatiy [6.2K]

With digits 8, 5, and 6, an odd number must end in 5.
So far, we have _ _ 5.
The 8 is in the hundreds place.
Now we have 8_5.
The only place left for the 6 is the tens place.
The number is 865.

6 0

3 years ago

Write an equation of the line perpendicular to the given line that contains P.

lara31 [8.8K]

Answer:

Step-by-step explanation:

perp. -5

y + 7 = -5(x - 4)

y + 7 = -5x + 20

y = -5x + 13

7 0

3 years ago

A company is expanding its building area from 20,000 square feet to 27,400 square feet. What is the percentage increase of the a

choli [55]

Answer:

can u help md on my question plssssssss

Step-by-step explanation:

I really need ur help pls can u help me my work is due in t mins and I need help pls.

4 0

3 years ago

I need help with this assignment

serious [3.7K]

In this problem the big angle will be equal to two times the smaller angle so the correct expression is:

$\angle TUV=2\angle VUW$

Now we can rewrite the equation so:

$\angle VUW=\frac{1}{2}\angle TUV$

3 0

1 year ago

Polygon q is a scaled copy of polygon p using a scale factor of 1/2 polygon q’s area is what fraction of polygon p’s area?

san4es73 [151]

Answer:

Polygon q’s area is one fourth of polygon p’s area

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

z-----> the scale factor

x-----> polygon q’s area

y-----> polygon p’s area

so

$z^{2} =\frac{x}{y}$

In this problem we have

$z=\frac{1}{2}$

substitute

$(\frac{1}{2})^{2} =\frac{x}{y}$

$(\frac{1}{4}) =\frac{x}{y}$

$x=\frac{1}{4}y$

therefore

Polygon q’s area is one fourth of polygon p’s area

3 0

3 years ago

Read 2 more answers