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3 years ago

1) Is 11 an irrational number? yes no Submit Yea

Mathematics

1 answer:

slamgirl [31]3 years ago

5 0

Answer:

YES

Step-by-step explanation:

Most real numbers (points on the number-line) are irrational (not rational). The rational numbers are those which have repeating decimal expansions (for example 1/11=0.09090909..., and 1=1.000000...=0.999999...) . They are also those which have terminating continued fraction expansions.

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4x/3 + 2(3- x) = 5 Solve for x as an FRACTION

forsale [732]

Answer:

<h2>The answer is .... x = 3/2 and if you want to write it as a mixed fraction i will be x= 1 and 1/2</h2>

Step-by-step explanation:

Hope this Helped :)

6 0

3 years ago

Factor the expression completely over the complex numbers. x^3-4x^2+4x-16

Orlov [11]

First you must know that is i∧2= -1

x∧3-4x∧2+4x-16 = x∧2 (x-4) + 4 (x-4) = (x-4) (x∧2+4) = (x-4) (x∧2-(-4)) =

= (x-4) (x∧2-(-1) *4) = (x-4) (x∧2- i∧2*2∧2) = (x-4) (x∧2-(2i)∧2) = (x-4) (x-2i) (x+2i)

Good luck!!!

5 0

3 years ago

Simplify. Your answer should contain only positive exponents. -2^х

polet [3.4K]

Answer: I'm not entirely sure, but maybe 1/x^2?

8 0

3 years ago

Solve for x. 5+x+(−2)=−8

levacccp [35]

5+х-2+8=0
х+5-2+8=0
х+11=0
х=0-11
х=-11

7 0

3 years ago

Write the point-slope form of the equation of the line through the given point with the given

UNO [17]

Answer:

The point-slope form of the equation is:

$y-\left(-5\right)=-3\left(x-3\right)$

Step-by-step explanation:

Given

point (3, -5)

slope = -3

We know the point-slope form of the line equation is

$y-y_1=m\left(x-x_1\right)$

where m is the slope

substituting the values m = -3 and the point (3, -5)

$y-y_1=m\left(x-x_1\right)$

$y-\left(-5\right)=-3\left(x-3\right)$

Thus, the point-slope form of the equation is:

$y-\left(-5\right)=-3\left(x-3\right)$

6 0

2 years ago