All categories

3 years ago

Work out the answer to this equation: 4e x 3f=

Mathematics

1 answer:

Helen [10]3 years ago

7 0

Answer:

12ef

Step-by-step explanation:

please mark as brainliest

You might be interested in

A STUDENT FINISHES THEIR FISR HALF OF AN EXAM IN 2/3 THE TIME IT TAKES HIM TO FINISH THE SECOND HALF. IF THE ENTIRE EXAM TAKES H

shepuryov [24]

Answer: First half was 24 minutes

Step-by-step explanation:

Let the time taken to finish the second half be y.

Since the student used 2/3 of the second half time to finish the first half, first half = 2/3 × y = 2y/3

The entire exam is an hour which equals 60 minutes

First half + Second half = 60minutes

Note that first half is denoted as 2y/3 and second half is denoted by y.

2y/3 + y = 60

5y/3 = 60

Cross multiply

5y = 60 × 3

5y = 180

y = 180/5

y = 36

Second half took 36 minutes

Since first half is 2y/3, it will be:

(2×36) / 3

= 72/3

= 24minutes

First half took 24 minutes.

8 0

3 years ago

Miss Davis buys a loaf of bread for $4.25 and sevreal cans of soup for $1.50 each Miss Lee Buys Loaf of bread for the same cost

lina2011 [118]

Answer:

y= x less than 1.5 +4.25

Step-by-step explanation:

5 0

3 years ago

Function: Yes or no<br> {(-4,6),(-3,2),(1,0), (7,6), (8,2)}

LekaFEV [45]

Answer:

Step-by-step explanation:

3 0

2 years ago

Shawna lives in an apartment 9 4/5 miles from the hospital where she works. Her brother rents a room in a house 7 2/5 miles from

tamaranim1 [39]

Answer:

2 2/5 miles

Step-by-step explanation:

6 0

2 years ago

a car purchased for $34,000 is expected to lose value, or depreciate, at a rate of 6% per year.using x for years and y for the v

Vika [28.1K]

Answer:

$y = 34000(1-0.06) ^ t$

After 7.40 years it will be worth less than 21500

Step-by-step explanation:

This problem is solved using a compound interest function.

This function has the following formula:

$y = P(1-n) ^ t$

Where:

P is the initial price = $ 34,000

n is the depreciation rate = 0.06

t is the elapsed time

The equation that models this situation is:

$y = 34000(1-0.06) ^ t$

Now we want to know after how many years the car is worth less than $ 21500.

Then we do y = $ 21,500. and we clear t.

$21500 = 34000(1-0.06) ^ t\\\\log(21500/34000) = tlog(1-0.06)\\\\t = \frac{log(21500/34000)}{log(1-0.06)}\\\\t = 7.40\ years.$

After 7.40 years it will be worth less than 21500

3 0

3 years ago