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Anettt [7]
3 years ago
14

Work out the answer to this equation: 4e x 3f=

Mathematics
1 answer:
Helen [10]3 years ago
7 0

Answer:

12ef

Step-by-step explanation:

please mark as brainliest

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5th grade math. correct answer will be marked brainliest
Yuliya22 [10]

Answer:

4ft, 7 inches

Step-by-step explanation:

4 ft (48 inches), 7 inches

4 0
3 years ago
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I need help with this question please!!!
stealth61 [152]

Answer:

Step-by-step explanation:

Each point of function b(x) is shifted by rule

x -----> ( x - 2 )

and

y -----> (y + 3)

( - 1.5, 0) ------> (- 3.5, 3)

(- 1, - 1) -----> ( - 3, 2)

(0, - 2) ------> ( - 2, 1)

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5 0
3 years ago
Evaluate the integral. (remember to use absolute values where appropriate. Use c for the constant of integration.) 5 cot5(θ) sin
ozzi

I=5\int \frac{cos^{4}\theta }{sin\theta }\times cos\theta d\theta \\\\I=5\int \left ( 1-sin^{2}\theta  \right )^{2}\times \frac{cos\theta }{sin\theta }d\theta \\put\ \sin\theta =t\\\\dt=cos\theta d\theta \\\\I=5\int\frac{t^{4}+1-2t^{2}}{t}dt\ \ \ \ \ \ \ \ \ \ \because (a-b)^2=a^2+b^2-2ab\\\\I=5\left ( \int t^{3}dt + \int \frac{1}{t} -2\int t \right )dt

by using the integration formula

we get,

\\I=5\left ( \frac{t^{4}}{4} +logt -t^{2}\right )\\\\I=\frac{5}{4}t^{4}+5\log t-5t^{2}+c

now put the value of t=\sin\theta in the above equation

we get,

\int 5\cot^5\theta \sin^4\theta d\theta=\frac{5}{4}sin^{4}\theta+5\log \sin\theta - 5sin^{2} \theta+c

hence proved

7 0
3 years ago
How do you understand it
maks197457 [2]
431 ≈ 400
115 ≈ 100
400 - 100 = 300
3 0
4 years ago
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Question 3 of 56
Mumz [18]

Answer:

only B

Step-by-step explanation:

since A) its 180+6 which absolutely greater than 9

C)31-1=30 which is greater than 8

D) 4 is greater than 3

4 0
2 years ago
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