Solution
if the number _C__ is a root of a polynomial, then x-c is a factor.
Whenever we have a polynomial
Example
![undefined](https://tex.z-dn.net/?f=undefined)
Answer:
p=1.2
Step-by-step explanation:
Additive inverse of any number means a number which can be added to the original number to get
Two numbers are said to be additive inverse of each other if sum of both numbers is 0. For example if 5 is the given number then -5 will be it's additive inverse. So to find additive inverse, we basically change the sign of number.
Given number p is additive inverse off -1.2 so p must be 1.2.
Sum will obviously be 0.
So to graph them on number line, we make a point at -1.2, 1.2 and at 0 for their sum.
Identity to verify:
![\dfrac{\cot x}{1+\csc x}=\dfrac{\csc x-1}{\cot x}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Ccot%20x%7D%7B1%2B%5Ccsc%20x%7D%3D%5Cdfrac%7B%5Ccsc%20x-1%7D%7B%5Ccot%20x%7D)
Recall that
![\cos^2x+\sin^2x=1](https://tex.z-dn.net/?f=%5Ccos%5E2x%2B%5Csin%5E2x%3D1)
Divide both sides by
and we get
![\cot^2x+1=\csc^2x](https://tex.z-dn.net/?f=%5Ccot%5E2x%2B1%3D%5Ccsc%5E2x)
or
![\cot^2x=\csc^2x-1=(\csc x-1)(\csc x+1)](https://tex.z-dn.net/?f=%5Ccot%5E2x%3D%5Ccsc%5E2x-1%3D%28%5Ccsc%20x-1%29%28%5Ccsc%20x%2B1%29)
So if we multiply the numerator and denominator of
![\dfrac{\cot x}{1+\csc x}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Ccot%20x%7D%7B1%2B%5Ccsc%20x%7D)
by
, we get
![\dfrac{\cot x(\csc x-1)}{(1+\csc x)(\csc x-1)}=\dfrac{\cot x(\csc x-1)}{\csc^2x-1}=\dfrac{\cot x(\csc x-1)}{\cot^2x}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Ccot%20x%28%5Ccsc%20x-1%29%7D%7B%281%2B%5Ccsc%20x%29%28%5Ccsc%20x-1%29%7D%3D%5Cdfrac%7B%5Ccot%20x%28%5Ccsc%20x-1%29%7D%7B%5Ccsc%5E2x-1%7D%3D%5Cdfrac%7B%5Ccot%20x%28%5Ccsc%20x-1%29%7D%7B%5Ccot%5E2x%7D)
Then as long as
, we can cancel terms to end up with
![\dfrac{\csc x-1}{\cot x}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Ccsc%20x-1%7D%7B%5Ccot%20x%7D)
and establish the identity.
-52 (x - 97) = x + 39
-52x + 5,044 = x + 39
+52x +52x
5,044 = 53x + 39
-39 - 39
5,005 = 53x
____ ____
53x 53x
94.43 = x
Answer:
amino acids
Step-by-step explanation: