I think it’s 6
Sorry if I’m wrong
Using a system of equations, it is found that since 20 child bikes and 6 adult bikes would require more testing than the allocated time, it is not possible to build this amount.
<h3>What is a system of equations?</h3>
A system of equations is when two or more variables are related, and equations are built to find the values of each variable.
In this problem, the variables are:
- Variable c: number of child bikes.
- Variable a: number of adult bikes.
Each child bike requires 4 hours to build, as do each adult bike. The company has 100 hours of testing, hence:
4c + 4a = 100.
c + a = 25.
With 20 child bikes and 6 adult bikes in a week, we have that c = 20, a = 26, hence:
c + a = 26
20 child bikes and 6 adult bikes would require more testing than the allocated time, it is not possible to build this amount.
More can be learned about a system of equations at brainly.com/question/24342899
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You have to multiply whats outside the parenthesis with everything that is inside, so
![x^{-3}y^0.(x^2-3x^5y^4)](https://tex.z-dn.net/?f=x%5E%7B-3%7Dy%5E0.%28x%5E2-3x%5E5y%5E4%29)
![x^{-3}y^0.x^2-x^{-3}y^0.3x^5y^4](https://tex.z-dn.net/?f=x%5E%7B-3%7Dy%5E0.x%5E2-x%5E%7B-3%7Dy%5E0.3x%5E5y%5E4)
Multiplication of same bases we sum the exponents
![x^{-3+2}y^0-3x^{-3+5}y^{0+4}](https://tex.z-dn.net/?f=x%5E%7B-3%2B2%7Dy%5E0-3x%5E%7B-3%2B5%7Dy%5E%7B0%2B4%7D)
![x^{-1}.1-3x^2y^4](https://tex.z-dn.net/?f=x%5E%7B-1%7D.1-3x%5E2y%5E4)
![x^{-1}-3x^2y^4](https://tex.z-dn.net/?f=x%5E%7B-1%7D-3x%5E2y%5E4)
Alternative B.
You can set both fractions to have the same denominator by multiplying 6/8 (both the 6 and 8) by 2 to keep the value of the fraction, while turning the denominator to 16. So you get 12/16=y/16.
That means for the equation to be true y has to be 12.
Hope this helps!
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