4x - 91x + 8 = -87x + 8
6x - 4 + 2x + 9 = 8x + 5
8x + 3+ 7xy - 2 + x - 5xy = 2xy + 9x + 1
Hi,
8 Pckts each has 500 g weight .Total weight would be 8*500=4000g
and she arranged them into 3 boxes.
assume those three boxes are X,Y,Z first,second,thrid respectively.
X+Y+Z=4000g--------------------1
then according to the statement first box is twice heavy as second one
means X=2Y----------------2
and thrid box is 60g heavier than second box.
Z=Y+60--------------------3
put those values in to eq 1
2Y+Y+Z=4000
3Y+Y+60=4000
4Y=4000-60
4Y=3940
Y=985
second box weight is 985 gram
Here is your answer
Both
a) /_D
c) /_ADB
are correct
REASON:
/_ADB represents an angle between AD and BD which is marked in the question.
/_D represents the point where the two lines or rays have a common point, i.e.D
[However writing a single letter to represent an angle is not completely correct. But when there is only one angle represented through the point then writing a single letter is correct
i.e. /_D is correct ]
HOPE IT IS USEFUL
Answer:
63
Step-by-step explanation:
In these 9 bags, each must have 7 gumdrops. So, we can add 7 nine times to itself. 7 + 7 + 7 + 7 + ... = 63
OR HERE'S A FASTER WAY *WINK WINK*
Instead of doing repeated addition, we can <u>multiply</u> 7 and 9 together.
<u>Why multiply?</u>
We're going to multiply 7 x 9 so that it means seven gumdrops for <em>each</em> of nine bags.
7 x 9 = 63.
Answer:
A: 2
B: -1/3
Step-by-step explanation:
A: We are looking for the common ratio between the terms of the sequence, which is essentially what you are multiplying by to get from one term to the next. To find this, we just have to divide the second term by the first term.
-4 / -2 = 2, therefore our common ratio is 2.
We can check this by continuing to multiply the next terms by 2 - -4 x 2 = -8, -8 x 2 = -16, so the pattern works.
B: For B, we will do exactly the same method as before: 3/-9 = -1/3, so our multiplier is -1/3.
To check: 3 x -1/3 = -1, and -1 x -1/3 = 1/3, which both follow our rule.
Hope this helps! Let me know if you have any questions.
