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ryzh [129]
3 years ago
10

Lemme know ——————————-

Mathematics
1 answer:
vichka [17]3 years ago
5 0

Answer:

121

Step-by-step explanation:

180 - (56 + 65) = 59

180 - 59 = 121

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2-2 asigment álgebra 1
Rainbow [258]

Answer:

2-2=0 because they cancel each other out

7 0
3 years ago
Simplify the expression to a polynomial in standard form:<br> (3x+1)(2x^2-5x+7)
Ilia_Sergeevich [38]

Answer:

6x^3-13x^2+16x+7

Step-by-step explanation:

(3x+1)(2x^2-5x+7)

6x^3-15x^2+21x+2x^2-5x+7

6x^3-15x^2+2x^2+21x-5x+7

6x^3-13x^2+16x+7

5 0
3 years ago
Find the measures of x and y. (Please answer correctly, with steps on how you got your answer as well please)
puteri [66]

Answer:

x= 65 º

y= 25 º

Step-by-step explanation:

8 0
3 years ago
In △ABC, point D∈ AC with AD:DC=4:3, point E∈ BC so that BE:EC=1:5. If ACDE=5 in2, find ABDC, AABD, and AABC.
Kaylis [27]

Answer:

ar ΔBDC=6 in^2

ar ΔABD=8 in^2

ar ΔABC=14 in^2

Explanation:

Please take a look of attach figure.

We are given area of triangle ar ΔCDE=5 in^2

ar ΔCDE=\frac{1}{2}\times DN\times EC------------(1)

ar ΔBDE=\frac{1}{2}\times DN\times BE------------(2)

Divide eq(2) by eq(1) and we get,

\frac{ar\ ΔBDE}{ar\ ΔCDE}=\frac{BE}{EC}

\frac{ar\ ΔBDE}{5}=\frac{1}{5}

So, ar ΔBDE=1 in^2

ar ΔBDC=ar ΔBDE+ ar ΔCDE

ar ΔBDC=1+5 = 6 in^2

Similarly,

\frac{ar\ ΔABD}{ar\ ΔBDC}=\frac{AD}{DC}

\frac{ar\ ΔABD}{6}=\frac{4}{3}

ar ΔABD=8 in^2

ar ΔABC=ar ΔABD + ar ΔBDC

ar ΔABC=8+6 = 14 in^2

6 0
3 years ago
Please answer correctly !!!!!!! Will mark brainliest !!!!!!!!!!!
ale4655 [162]

Answer:

f(x) = x^2 - 2x + 12

Step-by-step explanation:

the f(x) equation has a y-intercept of 12 because f(x)=x^2 - 2x has a y-intercept of 0 and the + 12 at the end shifts the function up 12 units putting the y-intercept at (0,12) while on the graph of the function g(x) it intercepts the y-axis at (0,1).

4 0
3 years ago
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