Complete the square for x2-10x+17=-y2-2y

At a local museum, a statue must be at least 187 centimeters tall for display purposes. Rita wants to give the museum the statu

Inessa05 [86]

Answer:

yes

Step-by-step explanation:

C.

3 0

1 year ago

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For the graph of the inequality x - 2y >4, what is a value of x for a point that is on the

Colt1911 [192]

Answer:

Step-by-step explanation:

Explanation:

First, find two points on the line if you change the inequality to an equation.

For

x

=

0

:

0

+

2

y

=

4

2

y

=

4

2

y

2

=

4

2

y

=

2

or

(

0

,

2

)

For

y

=

0

:

x

+

0

=

4

x

=

4

or

(

4

,

0

)

We can plot these two points and draw a line through them to get the border of the inequality:

graph{(x^2+(y-2)^2-0.075)((x-4)^2+y^2-0.075)(x+2y-4)=0}

The line will be solid because the inequality operator has a "or equal to" clause in it. We can now shade the area to the right of the line because the inequality has a "great than" clause in it.

graph{(x+2y-4)>=0}

4 0

2 years ago

a piece of gum is stuck to the tire of a bike wheel in motion. The vertical distance between the gum and the ground, in centimet

melamori03 [73]

Answer:

im not too sure but i got the exact same answers witten down i j have to find it

Step-by-step explanation:

8 0

2 years ago

contractor A estimated a job would cost $54,000 to complete in 90 days. contractor B estimated he could complete the same job fo

Genrish500 [490]

I think A does 600 and B does 412.50

4 0

2 years ago

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The radius of a hailstone varies directly with

maw [93]

Answer:

Hailstone remained in the cloud for 25 seconds.

Step-by-step explanation:

Radius of a hailstone varies directly with the duration for which it was in the cloud.

Let the radius of the hailstone is 'r' and it was in the cloud for 't' seconds.

r ∝ t

r = kt [ k is the proportionality constant]

If r = 0.5 inches and t = 10 seconds

Then, 0.5 = k × 10

k = $\frac{0.5}{10}$

k = 0.05

Now we have to find the duration t for which hailstone was in the cloud having radius = 1.25 inches.

1.25 = 0.05 × t

t = $\frac{1.25}{0.05}$

t = 25 second

Therefore, hailstone remained in the cloud for 25 seconds.

4 0

3 years ago