We take the equation <span>d = -16t^2+12t</span> and subtract d from both sides to get
0<span> = -16t^2+12t - d
We apply the quadratic formula to solve for t. With a = -16, b = 12, c = -d, we have
t = [ -(12) </span><span>± √( 12^2 - 4(-16)(-d) ) ] / [2 * -16]</span>
= [- 12 ± √(144-64d) ] / (-32)
= [- 12 ± √16(9-4d)] / (-32)
= [- 12 ± 4√(9-4d)] / (-32)
= 3/8 ±√(9-4d) / 8
The answer to your question is t = 3/8 ±√(9-4d) / 8
Easy
y=a(x-h)^2+k
vertex is (h,k)
we know that vertex is (4,0)
input that point for (h,k)
y=a(x-4)^2+0
y=a(x-4)^2
passes thorugh the point (6,1)
input that point to find a
1=a(6-4)^2
1=a(2)^2
1=a(4)
divide both sides by 4
1/4=a
thefor the equation is
y=(1/4)(x-4)^2
or
y=(1/4)x^2-2x+4
<u>Answer:</u>
143°
option c is correct!
<u>Explanation:</u>
Given:
Two angles are supplementary:
One angle = 37°
We know if two angles are supplementary their sum is equal to 180°.
Let another angle be x°
= > 37° + x° = 180
= > x° = 143°
Therefore another angle is 143°.
Answer: Dim Col A = 4.
Step-by-step explanation:
Since we have given that
Matrix A has 5 rows and 8 columns.
And Nul A = 4
It implies that the rank of A would be
Number of columns - Nul A = 8 - 4 =4
So, rank A = 4
so, it has dim Col A = 4 also.
But the four vector basis lie in R⁵.
Hence, Dim Col A = 4.
