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Shkiper50 [21]
2 years ago
9

2x} }{\sqrt{} x-1}" alt="\frac{\sqrt{2x} }{\sqrt{} x-1}" align="absmiddle" class="latex-formula">
For which values of x does each expression make sense?
Mathematics
1 answer:
Lubov Fominskaja [6]2 years ago
4 0

Answer:

The expression is unclear so:

If the denominator is \sqrt{x}-1 then your set of existence is given by

\left \{ {{x\ge0} \atop {x\ne1}} \right.

since you want the quantity inside both square roots to be positive (and it happens for both to be simply x\ge0 and you don't want a zero at the denominator so you have to rule out 1.

If the square root includes the whole denominator \sqrt{x-1} the condition becomes \left \{ {{x\ge0} \atop {x>1}} \right.

where you don't include the extreme in the second condition since, again, you don't want to divide by 0. The answer in this case is simply x>1 since values between 0 and 1 will give a negative root which is not a real number.

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AfilCa [17]

Answer:

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Step-by-step explanation:

The equation can be written in vertex form by adding and subtracting 25:

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7 0
3 years ago
Hall and Mindy are playing a guessing game. Hall tells Mindy: ""The difference between 17 and the square root of my mystery numb
cestrela7 [59]

Answer:

The possible number that Hall could be thinking of is 144.

Step-by-step explanation:

Difference between 17 and the square root of my mystery number

This is represented by:

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Then:

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(\sqrt{x})^2 = (12)^2

x = 144

The possible number that Hall could be thinking of is 144.

5 0
3 years ago
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ollegr [7]

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6 0
3 years ago
Read 2 more answers
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Step-by-step explanation:

3 0
3 years ago
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Which expression is equivalent to negative 32 5/3?
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Im confused. Its not equal to any of the choices

Unless C  is the cube root of 32^5.

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6 0
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