Answer:
≈23.6 kg left.
Step-by-step explanation:
For determining this, we can simply use an exponential decay equation representing this scenario:
a: the initial amount
t: the amount of time
h: the half life
Now, substitute the numbers into the equation:
Now, solve this equation:
Use a calculator to solve for y:
y= 200(0.118)
y≈23.6 kg left.
Answer with explanation:
An Unbiased Dice is Rolled 199 times.
Frequency of outcomes 1,2,3,4,5,6 are=28, 29, 47, 40, 22, 33.
Probability of an Event
→→→To check whether the result are significant or not , we will calculate standard error(e) and then z value
1.
→→If the value of z is between 2 and 3 , then the result will be significant at 5% level of Significance.Here value of z is very less, so the result is not significant.
2.
Result is not significant.
3.
Result is not significant.
4.
Result is not significant.
5.
Result is not significant.
6.
Result is not significant.
⇒If you will calculate the mean of all six z values, you will obtain that, z value is less than 2.So, we can say that ,outcomes are not equally likely at a 0.05 significance level.
⇒⇒Yes , as Probability of most of the numbers that is, 1,2,3,4,5,6 are different, for a loaded die , it should be equal to approximately equal to 33 for each of the numbers from 1 to 6.So, we can say with certainty that loaded die behaves differently than a fair die.