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2 years ago

Help me i need it to pass

Mathematics

1 answer:

Harrizon [31]2 years ago

5 0

The answer is 8.

8x4=32

(8x7)-(8x3)=32

Hope this helps!

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Find the tangent line approximation for 10+x−−−−−√ near x=0. Do not approximate any of the values in your formula when entering

Svetllana [295]

Answer:

$L(x)=\sqrt{10}+\frac{\sqrt{10}}{20}x$

Step-by-step explanation:

We are asked to find the tangent line approximation for $f(x)=\sqrt{10+x}$ near $x=0$ .

We will use linear approximation formula for a tangent line $L(x)$ of a function $f(x)$ at $x=a$ to solve our given problem.

$L(x)=f(a)+f'(a)(x-a)$

Let us find value of function at $x=0$ as:

$f(0)=\sqrt{10+x}=\sqrt{10+0}=\sqrt{10}$

Now, we will find derivative of given function as:

$f(x)=\sqrt{10+x}=(10+x)^{\frac{1}{2}}$

$f'(x)=\frac{d}{dx}((10+x)^{\frac{1}{2}})\cdot \frac{d}{dx}(10+x)$

$f'(x)=\frac{1}{2}(10+x)^{-\frac{1}{2}}\cdot 1$

$f'(x)=\frac{1}{2\sqrt{10+x}}$

Let us find derivative at $x=0$

$f'(0)=\frac{1}{2\sqrt{10+0}}=\frac{1}{2\sqrt{10}}$

Upon substituting our given values in linear approximation formula, we will get:

$L(x)=\sqrt{10}+\frac{1}{2\sqrt{10}}(x-0)$

$L(x)=\sqrt{10}+\frac{1}{2\sqrt{10}}x-0$

$L(x)=\sqrt{10}+\frac{\sqrt{10}}{20}x$

Therefore, our required tangent line for approximation would be $L(x)=\sqrt{10}+\frac{\sqrt{10}}{20}x$ .

8 0

2 years ago

Lets play a division game 3,072÷32

mario62 [17]

3,072 ÷ 32 = 96

Hope this helps

6 0

2 years ago

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99 times the sum of v and 9

pav-90 [236]

99 (v + 9) is the answer

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2 years ago

If one square yard costs 12 dollars how much is 180 square feet

Mumz [18]

12 x 180 is equal to 2160. It would cost $2160

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You take your friend out to dinner for their birthday. The bill was $65.00. You left $75.00 which includes the tip. What was the

kenny6666 [7]

Answer:

6.5%

Step-by-step explanation:

All i did was subtract 65 from the 75 which gave me 10 and I divided that by the original cost which was 65. That gave me 6.5%. Another possible answer is 0.1538461538461538. I just tried my best.

6 0

2 years ago