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2 years ago

8

Find the slope of the line passing through the points and .

1 answer:

sergejj [24]2 years ago

6 0

Answer:

slope = - $\frac{7}{5}$

Step-by-step explanation:

Calculate the slope m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (3, 4 ) and (x₂, y₂ ) = (8, - 3 )

m = $\frac{-3-4}{8-3}$ = $\frac{-7}{5}$ = - $\frac{7}{5}$

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60 is what percent of 200...
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3 years ago

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I need to increase my sales by 35% this month I’m currently at 45 sales how many sales do I need to meet my goal ?

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Assume that 100% = 45 sales and 35% = X sales amount

You can create a ratio to help you solve for x

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3 years ago

Solve the inequality and express your answer in interval notation<br> x^2+8x+5 <0

irakobra [83]

The interval notation is $(-\sqrt{11}-4, \sqrt{11}-4)$

Explanation:

The inequality is $x^{2}+8 x+5$

Let us complete the square, we get,

$x^{2}+8 x+5+4^{2}-4^{2}$

Simplifying, we have,

$(x+4)^{2}+5-4^{2}$

$(x+4)^{2}-11$

Adding both sides of the equation by 11, we get,

$(x+4)^{2}$

Since, we know that for $u^{n}$ , if n is even then $-\sqrt[n]{a}$

Thus, writing the above expression in this form, we get,

$-\sqrt{11}$

Also, if $a$ then $a$ and $u$

Then ,we have,

$-\sqrt{11}$ and $x+4$

Solving the inequalities, we get,

$-\sqrt{11}\ \ \ \ \ \$ and $x+4$

Merging the intervals, we have,

$-\sqrt{11}-4$

Hence, writing the solution in interval notation, we have,

$(-\sqrt{11}-4, \sqrt{11}-4)$

Therefore, the answer is $(-\sqrt{11}-4, \sqrt{11}-4)$

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3 years ago

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Hatshy [7]

Answer:

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Step-by-step explanation:

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