Replace x with π/2 - x to get the equivalent integral

but the integrand is even, so this is really just

Substitute x = 1/2 arccot(u/2), which transforms the integral to

There are lots of ways to compute this. What I did was to consider the complex contour integral

where γ is a semicircle in the complex plane with its diameter joining (-R, 0) and (R, 0) on the real axis. A bound for the integral over the arc of the circle is estimated to be

which vanishes as R goes to ∞. Then by the residue theorem, we have in the limit

and it follows that

Answer:
I think they are SAS but I'm not sure
Answer:
-3 + -6= -9
because there is answer given
He circumference of a circle<span> is equal to the diameter times pi. So, let's look at </span>what happens<span> if you double the </span>radius<span> of a </span>circle<span> -- say from 2 to 4. The area will go from 12.56 to 50.24. This means that it has </span>quadrupled<span>.</span>