Question

If 50. 0 g of ch₃oh (mm = 32. 04 g/mol) are added to a 500. 0 ml volumetric flask, and water is added to fill the flask, what is the concentration of ch₃oh in the resulting solution?.

Answer 1

Taking into account the definition of molarity, the concentration of CH₃OH in the solution is 3.12 $\frac{moles}{liters}$.

Definition of molarity

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

$Molarity=\frac{number of moles}{volume}$

Molarity is expressed in units $\frac{moles}{liters}$.

Concentration of CH₃OH

In this case, you know:

• number of moles= 50 g× $\frac{1 mole}{32.04 g}$= 1.56 moles, being 32.04 $\frac{g}{mole}$ the molar mass of CH₃OH
• volume= 500 mL= 0.5 L (being 1000 mL= 1 L)

Replacing in the definition of molarity:

$Molarity=\frac{1.56 moles}{0.500 L}$

Solving:

Molarity= 3.12 $\frac{moles}{liters}$

Finally, the concentration of CH₃OH in the solution is 3.12 $\frac{moles}{liters}$.

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