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3 years ago

If answered and explained properly, BRAINLIEST will be given.

Mathematics

1 answer:

ale4655 [162]3 years ago

8 0

so initially the paper is in full piece.

it is cut into half, which makes into 2. this is pattern 1.

then the halves is further divided in to 2.

then the total becomes 4. then the four pieces are cut into halves, which makes the total of 8 pieces, that is pattern 3..

is if we see the pattern it is a geometric progression.

Tn=ar²-¹ where the r is common ratio

and a is the first term. the question mentioned repeat 15 times.

1. 2

2. 4

3. 8

4. 16

4÷2=2 the common ratio.

So T(15)= 2×2¹⁵-¹

2×2¹⁴

2¹⁵

32768 pieces

please mark brainliest.

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Solve for x. 9x - 1 = -11 x = -1 x = -1 x = 1 x = 1

Dmitriy789 [7]

Answer:

x=-1

Step-by-step explanation:

Add by 1 from both sides of equation.

9x-1+1=-11+1

Simplify.

-11+1=-10

9x=-10

Divide by 9 from both sides of equation.

9x/9=-10/9

Simplify, to find the answer.

x=-10/9

x=-1 is the correct answer.

I hope this helps you, and have a wonderful day!

6 0

4 years ago

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Which of the following fractions can be represented by a terminating decimal? A. 8/9 B. 13/8 C. 4/3 D. 6/11

goblinko [34]

Answer:

Step-by-step explanation:

13/8 because when simplified into a decimal would be 1.625 and if you round would be 2 so you take out the decimal

4 0

4 years ago

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9/10 greater than 6/8

Citrus2011 [14]

Yes.

First, you find the fractions with common denominators: 9/10 is equal to 72/80 and 6/8 is equal to 60/80.

Since 72 is greater than 60, 9/10 is greater than 6/8.

7 0

3 years ago

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Verify the identity. cotangent of x divided by quantity one plus cosecant of x equals quantity cosecant of x minus one divided b

Elenna [48]

Answer:

$\frac{\cot x}{1+\csc x}=\frac{\csc x-1}{\cot x}$

Step-by-step explanation:

We want to verify the identity:

$\frac{\cot x}{1+\csc x}=\frac{\csc x-1}{\cot x}$

Let us take the LHS and simplify to get the LHS.

Express everything in terms of the cosine and sine function.

$\frac{\cot x}{1+\csc x}=\frac{\frac{\cos x}{\sin x} }{1+\frac{1}{\sin x} }$

Collect LCM

$\frac{\cot x}{1+\csc x}=\frac{\frac{\cos x}{\sin x} }{\frac{\sin x+1}{\sin x} }$

We simplify the RHS to get:

$\frac{\cot x}{1+\csc x}=\frac{\cos x}{\sin x+1}$

We rationalize to get:

$\frac{\cot x}{1+\csc x}=\frac{\cos x(\sin x-1)}{(\sin x+1)*(\sin x-1)}$

We expand to get:

$\frac{\cot x}{1+\csc x}=\frac{\cos x(\sin x-1)}{\sin^2 x-1}$

Factor negative one in the denominator:

$\frac{\cot x}{1+\csc x}=\frac{\cos x(\sin x-1)}{-(1-\sin^2 x)}$

Apply the Pythagoras Property to get:

$\frac{\cot x}{1+\csc x}=\frac{\cos x(\sin x-1)}{-\cos^2 x}$

Simplify to get:

$\frac{\cot x}{1+\csc x}=\frac{-(\sin x-1)}{\cos x}$

$\frac{\cot x}{1+\csc x}=\frac{1-\sin x}{\cos x}$

Divide both the numerator and denominator by sin x

$\frac{\cot x}{1+\csc x}=\frac{\frac{1}{\sin x}-\frac{\sin x}{\sin x}}{\frac{\cos x}{\sin x}}$

This finally gives:

$\frac{\cot x}{1+\csc x}=\frac{\csc x-1}{\cot x}$

8 0

3 years ago

Find the pressure in N/m2 exerted by a force of 40 N on an area of 5 m2 N/m2

zaharov [31]

Answer:

$pressure = \frac{force}{area} \\ = \frac{40}{5} \\ = 8 \: N {m}^{ - 2}$

3 0

3 years ago