The taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 
/2!+...........
Given a function f(x)=9/x,a=-4.
We are required to find the taylor series for the function f(x)=8/x centered at the given value of a and a=-4.
The taylor series of a function f(x)=
Where the terms in f prime 
(a) represent the derivatives of x valued at a.
For the given function.f(x)=8/x and a=-4.
So,f(a)=f(-4)=8/(-4)=-2.
(a)=(-4)=-8/(
=-8/16
=-1/2
The series of f(x) is as under:
f(x)=f(-4)+
=-2+2(x+4)/1!-24/16 /2!+...........
Hence the taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 /2!+...........
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A) Yes. we don't have enough information so this can not be determined.
B) No, it would just be an outlier.
The answer is c. 
a. 
(2.2≠5.11) (2.2 is not equal to 5.11)
b. 
or 0.625 (0.625≠5.11) (0.625 is not equal to 5.11)
c. 
(5.11=5.11) (5.11 is equal to 5.11)
Therefore c is the answer
For the last 2 questions,
1. 9/10
2. 7/12
Answer: There is a 90% chance that the true proportion of teenagers who drive their own car to school will lie in (0.5907, 0.9093).
Step-by-step explanation:
Interpretation of a% confidence interval : A person can be a% confident that the true population parameter lies in it.
Here, A 90% confidence interval to estimate the true proportion of teenagers who drive their own car to school is found to be (0.5907, 0.9093).
i.e. A person can be 90% confident that the true proportion of teenagers who drive their own car to school lies in (0.5907, 0.9093).
Hence, correct interpretation is : There is a 90% chance that the true proportion of teenagers who drive their own car to school will lie in (0.5907, 0.9093).
