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beks73 [17]
2 years ago
5

I NEED HELP LOLL

%20%3D%20" id="TexFormula1" title="7 \frac{1}{2} \div \frac{3}{4} = " alt="7 \frac{1}{2} \div \frac{3}{4} = " align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
harina [27]2 years ago
6 0

Answer:

the answer is 40/4

Step-by-step explanation: 7 1/4 3/4 40/4

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Use elimination to solve the system of equations.<br><br><br> –8x – 12y = 104<br> 10x + 12y = –124
swat32

Answer:

x = 10

Step-by-step explanation:

7 0
2 years ago
Drag each tile to the correct box.
rodikova [14]

Answer: C < B < A

<u>Step-by-step explanation:</u>

First, let's evaluate the growth rate of A from [1, 3]

f(x) = 200\bigg(\dfrac{3}{2}\bigg)^1

    = 300

coordinate is (1, 300)

f(x) = 200\bigg(\dfrac{3}{2}\bigg)^3

    = 675

coordinate is (3, 675)

Average growth rate (AGR) is: \dfrac{675-300}{3-1} = \dfrac{375}{2} = 187.5

AGR (A) = 187.5

*************************************************************************************

Next, let's evaluate the growth rate of B from [1, 3]

The coordinates are already provided as (1, 120) and (3, 480)

Average growth rate (AGR) is: \dfrac{480-120}{3-1} = \dfrac{360}{2} = 180

AGR (B) = 180

*************************************************************************************

Lastly, let's evaluate the growth rate of C from [1, 3]

f(x) = 600(1.2)ˣ

f(x) = 600(1.2)¹

     = 720

coordinate is (1, 720)

f(x) = 600(1.2)³

     = 1036.8

coordinate is (3, 1036.8)

Average growth rate (AGR) is: \dfrac{1036.8-720}{3-1} = \dfrac{316.8}{2} = 158.4

AGR (C) = 158.4

8 0
3 years ago
Sophia spent 7.30 for school supplies. She spent 3.00 for a notebook and 1.75 for a pen. She also bought 3 large erasers.If each
OverLord2011 [107]
$7.30 - (3.00+1.75) = $7.30 - $4.75 = $2.55
Divide by 3 (3 = number of erasers)
$2.55/3 = $0.85 per eraser.
8 0
3 years ago
Sarah kicked a ball in the air. The function
Aleksandr-060686 [28]

Answer: The ball hits the ground at 5 s

Step-by-step explanation:

The question seems incomplete and there is not enough data. However, we can work with the following function to understand this problem:

f=30 t- 6t^{2} (1)

Where f models the height of the ball in meters and t the time.

Now, let's find the time t when the ball Sara kicked hits the ground (this is when f=0 m):

0=30 t- 6t^{2} (2)

Rearranging the equation:

6t^{2}-30 t=0 (3)

Dividing both sides of the equation by 6:

t^{2}-5 t=0 (4)

This quadratic equation can be written in the form at^{2}+bt+c=0, and can be solved with the following formula:  

t=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a} (5)  

Where:  

a=1  

b=-5  

c=0  

Substituting the known values:  

t=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(0)}}{2(1)} (6)  

Solving we have the following result:

t=5 s  This means the ball hit the ground 5 seconds after it was kicked by Sara.

6 0
3 years ago
This line has a Y-intercept of <br><br>A. 0<br><br>B. 1<br><br>C.2<br><br>D.3​
insens350 [35]

Answer:

The y-intercept is 3 aka. (0,3)

Step-by-step explanation:

The slope is 1 (since (6-4)/(3-1)=2/2=1)

y=1x+b

4=1+b

3=b

4 0
3 years ago
Read 2 more answers
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