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2 years ago

15

A principal wants to find out how many hours per week the students in the school spend

1 answer:

malfutka [58]2 years ago

3 0

I think B (Every fifth student from each grade)

A only talks about female students, C talks about students on a sports team which would be biased since the students on the sports team probably get more exercise, and d would be ok but not the best since some last names are more common and others you would get only a very small sample size.

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What is pasture?

aliina [53]

Answer:

It says "I'm using rude words!"

3 0

2 years ago

Estimate the unit rate.<br> 283 students in 11 classes

Archy [21]

Answer:

So estimate.

Really depends on what needs to be estimated, the answer or the overall equation.
So doing the real one first.
283/11 = 25 8/11

You can’t have “part” of a student so rounding this you can go up since 8 is more then half of 11

So 26 students

If you were to round the overall equation then you’d get
280 / 10 which is 28 students per class

So two options.

5 0

2 years ago

A triangle has side lengths of 8 cm, 15 cm, and 17 cm. Classify it as acute, obtuse, or right.

Westkost [7]

Answer:

$15^{2}$ = 225

$8^{2}$ = 64

$17^{2}$ = 289

$15^{2}$ + $8^{2}$ + $17^{2}$

= 225 + 64 = 289

289 = 289

Hence its a right angled triangle

Hope it helps

Please mark me as the brainliest

Thank you

7 0

3 years ago

Pls help ASAP, will give barinliest

garik1379 [7]

Answer:

a

b

d

Step-by-step explanation:

im to lazy but subtract 180 and the others are equal just compare small angles to big ones and should equal 180

6 0

3 years ago

Read 2 more answers

Which strategies can be used to find the product of 629 x 100? Check all that apply.

dolphi86 [110]

Answer:

The strategies (2), (3) and (5) can be applied.

Step-by-step explanation:

In this case we need to compute the product of 629 × 100.

The product can be found in the following ways:

multiplying (600 + 20 + 9) x 100

$(600 + 20 + 9) \times 100=(600\times 100)+(20\times 100)+(9\times 100)\\=60000+2000+900\\=62900$

putting 2 zeros on the end of 629

$629\times 100=62900$

multiplying (6,000 + 200 +90) x 10

$(6000 + 200 + 90) \times 10=(6000\times 10)+(200\times 10)+(90\times 10)\\=60000+2000+900\\=62900$

Thus, the strategies (2), (3) and (5) can be applied.

5 0

3 years ago