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andriy [413]
2 years ago
8

Hussien says that the lcm of 6 and 4 is the same as the hcf of 36 and 24 is Hussein correct and why​

Mathematics
2 answers:
Lapatulllka [165]2 years ago
7 0

Answer:

LCM :

6 x 1 = 6

6 x 2 = 12

6 x 3 = 18

6 x 4 = 24

Meanwhile

4 x 1 = 4

4 x 2 = 8

4 x 3 = 12

4 x 4 = 16

4 x 5 = 20

4 x 6 = 24

The LCM of 6 and 4 is 12

HCF:

36 : 1,2,3,4,6,9,12,36

24 : 1,2,3,4,6,8,12,24

HCF of 36 and 24 is 12

So therefore Hussein is correct because both the LCM and HCF is 12

KatRina [158]2 years ago
7 0
Yes he is correct.
Explanation:
Because 36 & 24 has a hcf (highest common factor) of 12
And because 6 & 4 has lcm (least common multiple) of 12
To find out the lcm just go through their time table and find a common least multiple and to find out hcf just go through their time table and find a common highest factor.
Hope this helps! :)
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A group of researchers are interested in the possible effects of distracting stimuli during eating, such as an increase or decre
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Using the t-distribution, it is found that since the p-value of the test is of 0.0302, which is <u>less than the standard significance level of 0.05</u>, the data provides convincing evidence that the average food intake is different for the patients in the treatment group.

At the null hypothesis, it is <u>tested if the consumption is not different</u>, that is, if the subtraction of the means is 0, hence:

H_0: \mu_1 - \mu_2 = 0

At the alternative hypothesis, it is <u>tested if the consumption is different</u>, that is, if the subtraction of the means is not 0, hence:

H_1: \mu_1 - \mu_2 \neq 0

Two groups of 22 patients, hence, the standard errors are:

s_1 = \frac{45.1}{\sqrt{22}} = 9.6154

s_2 = \frac{26.4}{\sqrt{22}} = 5.6285

The distribution of the differences is has:

\overline{x} = \mu_1 - \mu_2 = 52.1 - 27.1 = 25

s = \sqrt{s_1^2 + s_2^2} = \sqrt{9.6154^2 + 5.6285^2} = 11.14

The test statistic is given by:

t = \frac{\overline{x} - \mu}{s}

In which \mu = 0 is the value tested at the null hypothesis.

Hence:

t = \frac{25 - 0}{11.14}

t = 2.2438

The p-value of the test is found using a <u>two-tailed test</u>, as we are testing if the mean is different of a value, with <u>t = 2.2438</u> and 22 + 22 - 2 = <u>42 df.</u>

  • Using a t-distribution calculator, this p-value is of 0.0302.

Since the p-value of the test is of 0.0302, which is <u>less than the standard significance level of 0.05</u>, the data provides convincing evidence that the average food intake is different for the patients in the treatment group.

A similar problem is given at brainly.com/question/25600813

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3 years ago
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3 years ago
What is the final amount if 468 is increased by 8% followed by a further 9%
bixtya [17]

Answer:

The final amount is  550.93.

Step-by-step explanation:

Here, the given amount is 468.

Now 8% of the given amount is \frac{8}{100}  \times 468  = 37.44

⇒ 8% of 468 =  37.44

So, the New amount = Initial Amount  + 8% increase

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Now 9 % of the new  amount 505.44  is

[tex]\frac{9}{100}  \times 505.44  = 45.4896/tex]

⇒ 9% of 505.44  = 45.4896

So, the Final  amount = New Amount  + 9% increase

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Hence,  final amount is  550.93.

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3 years ago
In order for terms to be like terms they must have?
tresset_1 [31]
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20x(5/100)=1

That is the interest after one year

Add to the principal:20+1=21

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2 years ago
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