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3 years ago

What is the solution to the equation?

Mathematics

2 answers:

Veseljchak [2.6K]3 years ago

3 0

Answer:

C. 7

Step-by-step explanation:

I hope this helped! Have a great day!

Lilac~

Andru [333]3 years ago

3 0

Answer:

Step-by-step explanation:

Answer is C

Have an amazing day!

Skye~

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Can someone explain? Please help! 15 pts!!!!

anygoal [31]

Let
x--------------> the third stone measure

we know that
the recommended height for the bench is ------> 20 in
20=[4 3/8]+[4 1/2]+[5 1/4]+[x]
4 3/8---------> (4*8+3)/8=35/8
4 1/2---------> (4*2+1)/2=9/2
5 1/4---------> (5*4+1)/4=21/4

20=[35/8]+[9/2]+[21/4]+[x]

x=20-(35/8)-(9/2)-(21/4)

x=20-(35+4*9+2*21)/8-----> 20-113/8------- > (8*20-113)/8

x=47/8---------- > 5.875=5 7/8

the answer is 5 7/8 in

3 0

3 years ago

Rachel jobs along the trail that was 1/4 of a mile long she jogged along the trail 8 times how many miles did Rachel job

son4ous [18]

2 miles is how long rachel jogged

4 0

3 years ago

D = -38t + 220

Kitty [74]

Answer: 38 meters per second

Step-by-step explanation:

4 0

2 years ago

Complete the identity. 1) sec^4 x + sec^2 x tan^2 x - 2 tan^4 x = ?

Alecsey [184]

Answer:

See Explanation

Step-by-step explanation:

Question like this are better answered if there are list of options; However, I'll simplify as far as the expression can be simplified

Given

$sec^4 x + sec^2 x tan^2 x - 2 tan^4 x$

Required

Simplify

$(sec^2 x)^2 + sec^2 x tan^2 x - 2 (tan^2 x)^2$

Represent $sec^2x$ with a

Represent $tan^2x$ with b

The expression becomes

$a^2 + ab- 2 b^2$

Factorize

$a^2 + 2ab -ab- 2 b^2$

$a(a + 2b) -b(a+ 2 b)$

$(a -b) (a+ 2 b)$

Recall that

$a = sec^2x$

$b = tan^2x$

The expression $(a -b) (a+ 2 b)$ becomes

$(sec^2x -tan^2x) (sec^2x+ 2 tan^2x)$

..............................................................................................................................

In trigonometry

$sec^2x =1 +tan^2x$

Subtract $tan^2x$ from both sides

$sec^2x - tan^2x =1 +tan^2x - tan^2x$

$sec^2x - tan^2x =1$

..............................................................................................................................

Substitute 1 for $sec^2x - tan^2x$ in $(sec^2x -tan^2x) (sec^2x+ 2 tan^2x)$

$(1) (sec^2x+ 2 tan^2x)$

Open Bracket

$sec^2x+ 2 tan^2x$ ------------------This is an equivalence

$(secx)^2+ 2 (tanx)^2$

Solving further;

................................................................................................................................

In trigonometry

$secx = \frac{1}{cosx}$

$tanx = \frac{sinx}{cosx}$

Substitute the expressions for secx and tanx

................................................................................................................................

$(secx)^2+ 2 (tanx)^2$ becomes

$(\frac{1}{cosx})^2+ 2 (\frac{sinx}{cosx})^2$

Open bracket

$\frac{1}{cos^2x}+ 2 (\frac{sin^2x}{cos^2x})$

$\frac{1}{cos^2x}+ \frac{2sin^2x}{cos^2x}$

Add Fraction

$\frac{1 + 2sin^2x}{cos^2x}$ ------------------------ This is another equivalence

................................................................................................................................

In trigonometry

$sin^2x + cos^2x= 1$

Make $sin^2x$ the subject of formula

$sin^2x= 1 - cos^2x$

................................................................................................................................

Substitute the expressions for $1 - cos^2x$ for $sin^2x$

$\frac{1 + 2(1 - cos^2x)}{cos^2x}$

Open bracket

$\frac{1 + 2 - 2cos^2x}{cos^2x}$

$\frac{3 - 2cos^2x}{cos^2x}$ ---------------------- This is another equivalence

8 0

3 years ago

Aileen purchased a box of ten juice boxes for her party. Each juice box contains eight unces of juice. At the end of the party,

adoni [48]

♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫

➷ 8 juice boxes were consumed, so that's 8*8=64 ounces gone. In total, there were 80 ounces, so 80-64=16.

64 ounces were consumed

16 ounces were left

✽

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

TROLLER

3 0

3 years ago