Answer:
Proved
Step-by-step explanation:
Given: EC || AC, DB || AC, ∠A = ∠F
Prove: ΔMDF ∼ ΔNCA
Solution
See diagram attached to the solution to better understand the following workings.
Redrawing ΔMDF or rotating to be facing the same direction.
EC is parallel to AC
DB parallel to AC
Using similar triangle theorem:
If ΔMDF ∼ ΔNCA
Ratio of Corresponding sides would be equal
(adjacent of ΔMDF)/(adjacent of ΔNCA) = (Opposite of ΔMDF)/(opposite of ΔNCA) = (hypotenuse of ΔMDF)/(hypotenuse of ΔNCA)
DF/ CA = MD/NC = FM/AN
∠A = ∠F
∠M = ∠N
∠D = ∠C
Since the ratio of Corresponding sides and angle are equal, ΔMDF is similar to ΔNCA.
ΔMDF ∼ ΔNCA
Answer:
Im not sure but i think 2 is the answer
Step-by-step explanation:
Answer:
Step-by-step explanation:
Distance=400+200=600km
diplacement=x 200-0km=200km
total distance travelled=400+400=800km
If 52 toys fit into a box and there are 92 boxes then the total toys would be 52 x 92 = 4,784
Answer:
It should be linear if you let the variable t represent the time tutoring for ONE student, so y = 40*t where t = number of hours for ONE student
so if the tutor taught 2 students for 2 hours together, then t = 2*2 = 4 hours
Step-by-step explanation:
y = 40t
t = tutoring hours for ONE unique student...