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3 years ago

If The number 0.1111... repeats forever; therefore, irrational number true or false?

Mathematics

2 answers:

IrinaK [193]3 years ago

7 0

True it's irrational !
if it repeats over and over like infine there you go bro!

Kazeer [188]3 years ago

4 0

False. This number can be written as a fraction, $\frac{1}{9}$

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Please help! Thank you :) also don't spam for points I know a moderator

dybincka [34]

Answer:

1) True

2) False

3) True

4) True

5) False

4 0

2 years ago

Which equation represent a relationship where y is a nonlinear function of x? Select all that apply

irina [24]

the question is a beat confusing please make it simplify

8 0

3 years ago

The area of the top face of a cube is 16 square inches. Use 8 of these cubes to make a rectangular

KengaRu [80]

Answer:

The volume of the rectangular prism is 512 inches³

Step-by-step explanation:

Any cube has 6 square faces

Area of any square = L × L, where L is a length of each side

The volume of the cube = L × L × L

∵ The area of the top face of a cube = 16 inches²

→ Find which number multiply by itself = 16

∵ 16 = L × L

∵ 16 = 4 × 4

∴ L = 4 inches

Let us find the volume of 1 cube

∵ The volume of the cube = L × L × L

∵ L = 4 inches

∴ The volume of each cube = 4 × 4 × 4

∴ The volume of each cube = 64 inches³

∵ We will use 8 of this cube to make a rectangular prism

→ That means the volume of the rectangular prism is 8 times

the volume of 1 cube

∴ The volume of the prism = 8 × volume of 1 cube

∵ The volume of each cube = 64 inches³

∴ The volume of the prism = 8 × 64

∴ The volume of the prism = 512 inches³

The volume of the rectangular prism is 512 inches³

5 0

3 years ago

Two stores sell the same television for the same original price. Store A

Mrac [35]

(0.7p)=p-250
30% off of p must be equal to 250 less than p. As a result you can say that 0.7p (0.7Xp), which is 70% of p (100%-30%=70%) is equal to p-250, so 0.7p=p-250.

6 0

3 years ago

Read 2 more answers

A sample of 4 different calculators is randomly selected from a group containing 18 that are defective and 35 that have no defec

Sphinxa [80]

<span>1.

P(</span>at least one of the calculators is defective)=

1- P(none of the selected calculators is defective).

2.

P(none of the selected calculators is defective)

=n(ways of selecting 4 non-defective calculators)/n(total selections of 4)

3.

selecting 4 non-defective calculators can be done in C(35, 4) many ways,

where $C(35, 4)= \frac{35!}{4!31!}= \frac{35*34*33*32*31!}{4!*31!}= \frac{35*34*33*32}{4!}= \frac{35*34*33*32}{4*3*2*1}= 52,360$

while, the total number selections of 4 out of 18+35=53 calculators can be done in C(53, 4) many ways,

$C(53, 4)= \frac{53!}{4!*49!}= \frac{53*52*51*50}{4*3*2*1}= 292,825$

4. so, P(none of the selected calculators is defective)= $\frac{52,360}{292,825} =0.18$

5. P(at least one of the calculators is defective)=

1- P(none of the selected calculators is defective)=1-0.18=0.82

Answer:0.82

7 0

3 years ago