1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vodomira [7]
3 years ago
10

100 POINTS AND BRAINLIEST!! PRE CALC

Mathematics
2 answers:
valkas [14]3 years ago
6 0

Answer:

b

Step-by-step explanation:

sin x = \frac{opposite}{hypotenuse} = \frac{3}{5}

This is a 3- 4- 5 right triangle

with adjacent side = 4 , then

cos x = \frac{adjacent}{hypotenuse} = \frac{4}{5} , thus

tan x = \frac{sinx}{cosx} = \frac{\frac{3}{5} }{\frac{4}{5} } = \frac{3}{5} × \frac{5}{4} = \frac{3}{4}

---------------------------------------------------

sin y = \frac{7}{25}

This is a 7- 24- 25 right triangle

with adjacent side = 24 , then

cos y = \frac{adjacent}{hypotenuse} = \frac{24}{25} , thus

tan y = \frac{siny}{cosy} = \frac{\frac{7}{25} }{\frac{24}{25} } = \frac{7}{25} × \frac{25}{24} = \frac{7}{24}

----------------------------------------------------

tan(x - y) = \frac{tanx-tany}{1+tanxtany}

             = \frac{\frac{3}{4}-\frac{7}{24}  }{1+\frac{3}{4}(\frac{7}{24})  }

             = \frac{\frac{11}{24} }{1+\frac{21}{96} }

             = \frac{\frac{11}{24} }{\frac{117}{96} }

             = \frac{11}{24} × \frac{96}{117}

             = \frac{11}{1} × \frac{4}{117}

             = \frac{44}{117} → b

goblinko [34]3 years ago
5 0

Answer:

B

Step-by-step explanation:

sinx = 3/5

to find the value of x...figure sine inverse(Arcsin) of 3/5 out.

sin^-1 ( 3/5) = 0.64.

siny = 7/25

sin^-1(7/25) = 0.28

x = 0.64

y = 0.28

tan(x-y)

=tan(0.64-0.28)

= tan (0.36)

= tan (9/25)

= 0.376.

now divide every fraction given from a - d to find the one equivalent to 0.376 because that's the value of tan(x-y).

B. 44 / 117 = 0.376.

You might be interested in
What is the equation to solve the volume of a cylinder?
elixir [45]

Answer:

See picture:)

Hope that makes sense! If you'd like any more help with maths, I'd be happy to offer online tuition. You can find me at: www.birchwoodtutors.com

8 0
3 years ago
I’m stuck on this question if someone could help me I would highly appreciate:)
kodGreya [7K]
Question 4 is (1,2)
Question 5 is (1,0)
These are are definitely correct
7 0
2 years ago
Prove that MNQ is congruent to PNQ (URGENT) help with all blanks
katrin2010 [14]

Answer:

In triangle QNP and QNM

3.QN=QN[common side]

so triangle QNP and QNM is CONGRUENT by A.A .S axiom.

4 0
3 years ago
Y''+y'+y=0, y(0)=1, y'(0)=0
mars1129 [50]

Answer:

y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )

Step-by-step explanation:

A second order linear , homogeneous ordinary differential equation has form ay''+by'+cy=0.

Given: y''+y'+y=0

Let y=e^{rt} be it's solution.

We get,

\left ( r^2+r+1 \right )e^{rt}=0

Since e^{rt}\neq 0, r^2+r+1=0

{ we know that for equation ax^2+bx+c=0, roots are of form x=\frac{-b\pm \sqrt{b^2-4ac}}{2a} }

We get,

y=\frac{-1\pm \sqrt{1^2-4}}{2}=\frac{-1\pm \sqrt{3}i}{2}

For two complex roots r_1=\alpha +i\beta \,,\,r_2=\alpha -i\beta, the general solution is of form y=e^{\alpha t}\left ( c_1\cos \beta t+c_2\sin \beta t \right )

i.e y=e^{\frac{-t}{2}}\left ( c_1\cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )

Applying conditions y(0)=1 on e^{\frac{-t}{2}}\left ( c_1\cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right ), c_1=1

So, equation becomes y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )

On differentiating with respect to t, we get

y'=\frac{-1}{2}e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )+e^{\frac{-t}{2}}\left ( \frac{-\sqrt{3}}{2} \sin \left ( \frac{\sqrt{3}t}{2} \right )+c_2\frac{\sqrt{3}}{2}\cos\left ( \frac{\sqrt{3}t}{2} \right )\right )

Applying condition: y'(0)=0, we get 0=\frac{-1}{2}+\frac{\sqrt{3}}{2}c_2\Rightarrow c_2=\frac{1}{\sqrt{3}}

Therefore,

y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )

3 0
3 years ago
An online company offers a package that includes 2 games for $11.98 they also offer a package that includes 5 games for $24.95 W
Olenka [21]

Answer:

the package that has five games

Step-by-step explanation:

divide both

4.99

and 5.99 4.99 is btter

6 0
3 years ago
Other questions:
  • 2 cubed minus 2 squared
    10·1 answer
  • Eric and Stephanie took their younger sister Melissa to pick apples. Eric picked 4 times as many apple as Melissa. Stephanie pic
    15·1 answer
  • Write an inequality to solve how many comic books would have Jose have to sell to make at least $100.
    15·1 answer
  • Why in math is X first (X,Y) but we graph Y first.
    5·1 answer
  • I have a test In math Tommorow and its a make or break situation for my grade I really need help with this question!
    6·2 answers
  • X + y = 9/x - y = 5?????
    14·1 answer
  • Which of the following answer choices correctly expresses the number 81? A. 3⁶ B. 3⁵ C. 3⁴ D. 3³​
    6·1 answer
  • Plz help me simply algebra problem
    10·1 answer
  • I NEED HELP ASAP PLEASE!!!
    13·1 answer
  • A university considers giving only pass/fail grades to freshmen to reduce competition and stress. The student newspaper intervie
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!